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Given the following table TABLE CUSTOMER Column Null? Туре CUS_ID NOT NULL NUMBER NAME VARCHAR2(50) CUS_PHONE VARCHAR2 (50) REGION_ID NUMBER The query that will return the number of regions which are assigned some customer is SELECT count( distinct region_id) FROM customer .a .b SELECT distinct count( distinct region_id) FROM customer .C SELECT distinct count(region_id) FROM customer SELECT countíregion id) FR OM.customer GROUP BY region id

Given the following table TABLE CUSTOMER Column Null? Туре CUS_ID NOT NULL NUMBER NAME VARCHAR2(50) CUS_PHONE VARCHAR2 (50) REGION_ID NUMBER The query that will return the number of regions which are assigned some customer is SELECT count( distinct region_id) FROM customer .a .b SELECT distinct count( distinct region_id) FROM customer .C SELECT distinct count(region_id) FROM customer SELECT countíregion id) FR OM.customer GROUP BY region id

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Given the following table TABLE CUSTOMER Column Null? Туре CUS_ID NOT NULL NUMBER NAME VARCHAR2 (50) CUS_PHONE VARCHAR2 (50) REGION_ID NUMBER The query that will return the number of regions which are assigned some customer is SELECT count( distinct region_id) FROM customer .a .b O SELECT distinct count( distinct region_id) FROM customer SELECT distinct count(region_id) FROM customer .c O .d o SELECT count(region_id) FROM customer GROUP BY region_id
Transcribed Image Text:Given the following table TABLE CUSTOMER Column Null? Туре CUS_ID NOT NULL NUMBER NAME VARCHAR2 (50) CUS_PHONE VARCHAR2 (50) REGION_ID NUMBER The query that will return the number of regions which are assigned some customer is SELECT count( distinct region_id) FROM customer .a .b O SELECT distinct count( distinct region_id) FROM customer SELECT distinct count(region_id) FROM customer .c O .d o SELECT count(region_id) FROM customer GROUP BY region_id
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