Given the function y = 8e-²x² + 7 sec² 5x – 4 ln x³, find y'. Solution: y' = 4(3)x² x³3 +8(−4x)e-²x² +7(2) sec 5x (sec² 5x) (5) 12 -32xe -2x² y' + 70 sec² 5x tan 5x x +8(-2x²)(-4x)e¯ -2x² +7 (2) sec 5x (sec² 5x)(5) 64x³e-2x² + 140 sec³ 5x ==

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A: The given problem is solved below in detail.