Given the general solution to a differential equation and its initial conditions y(t) = C,14 + C,-2 and y(1) = 6 and y'(1) = - 8 Find the value of C1 and C2 in order to find the specific solution to the differential equation. - 14 = 3 A 32 C, = 2 B 16 C, 5 3 - 19 C, 3 10 C, 7 D 32 %3D 7 3. 3.

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