Given the integral csc²u=cot²u+1 1+ cos2u 2 1-cos2u 2 sec²u=1+tan²u B cos²u=- sec (x-1) tan4 (x-1)dx, which of the following equations will be useful for evaluation? Ⓒsin²u=

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A: The function is given by y = x To evaluate: The instantaneous rate of change of the function at x=2.

Q: CALCULUS 2 1200-1330 TTh CALCULUS 2-FINAL TERM Exam 90 minutes remaining Oi Test Content Question 1…

A: Solve it

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A: topic - area bounded by curves

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A: Given query is to find the derivative at indicated point.

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A: A detailed solution is given below.

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A: Explained below

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A: integration

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A:

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A:

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Q: Hint: Use polar ca

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Q: Why is it "h • db/t + b • dh/dt"  instead of   "h • dh/dt  + b • db/dt"?

A: Using Rule of differentiation.

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A: (tan x)' = sec2(x) (eax)' = a eax.

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A: Topic:- application of integration

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A: We are allow to solve one question at a time . If you need rest of answers please upload it…

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A: Please see the below picture for detailed solution.

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A: We have to to slove derivative

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A:

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A: We have to find the angle α.

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A: Topic = Derivative

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A: The region bounded by the curves f(x)=ex, g(x)=e-x and x=3

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A: In order to integrate easily certain assumptions need to be made by using some variables.