Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. • Borrow Cost: $4.25/cu. yd. • Overhaul Cost: $1.25/sta*cu. yd. • Free Haul Limit: 600 ft. Compute the total excavation cost: $34,000.00 $10,000.00 $32,000.00 None of these. $26,000.00
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- Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 None of these. 11.7 6.0 O 8.0 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.25/cu. yd. Borrow Cost: $4.50/cu. yd. Overhaul Cost: $0.75/sta*cu. yd. Free Haul Limit: 600 ft. Compute the limit of economic haul: O 12.0 -3,000 1,500 5 2,100 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25Net Cumulative Yardage ● 5000 4000 3000 2000 C 1000 -1000 -2000 -3000 -4000 -5000 O 8.0 Compute the limit of economic haul: O None of these. 9.2 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. Borrow Cost: $3.25/cu. yd. Overhaul Cost: $1.25/sta*cu. yd. Free Haul Limit: 600 ft. 6.0 -3,000 9.4 1,500 10 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2,100 7.0 2000 8.0 1,500 1,500 8.0 ----- 1000 1,100 7.1 6.0 750 5.0 0. -1000 -2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total quantity of waste in cubic yards? O 2100 O 1500 400 O 750 O None of the above Net Cumulative Yardage
- Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 $10,590.00 Compute the total overhaul cost: O None of these. Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $3.75/cu.yd. Overhaul Cost: $1.50/sta*cu. yd. ● Free Haul Limit: 600 ft. O $1,590.00 5.0 O $600.00 -3,000 O $990.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2.100 7.0 2000 8.0 1,500 1,500 8.0 ------ 1000 -1,100 - 7.1 6.0 750 5.0 0. -1000 3-2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total cost in borrow to the nearest dollar? O $0 O $2,625 $2,813 $5,625 O Non Net Cumulative Yardage↑ NET CUMULATIVE YOS. 5,000 2,000 5 K-X1,000-31, 200 -(-)spoo MASS DIAGRAM 10 7.0 7.3 (-)2,500 1. What is the limit of economic haul in stations? 3. What is the overhaul cost in dollars? STATIONS 2. What is the total cost in dollars for excavation? 4. What is the total borrow cost in dollars? 5. What is the total waste in cubic yards? Limit of Free Haul Cost of Excavation Cost of Borrow Overhaul Price 15 ន 8.0 = 700 ft = $3.50 per cu.yd. = $3.00 per cu. yd. = $1.00 per sta yd. 25 -(-) 8000 (-11,000 (-)2,000 LENGTH IN STATIONS
- Given the data of a proposed highway END AREA (sq. m) Free Haul Distance, FHD = 50 m STATION CUT FILL Cost of Borrow = PHP6.00 per cu. m. 2+ 440 70 2+ 740 Cost of Excavation = PHP5.50 per cu. m. 3+ 040 50 Hauling Cost = PHPO.30 per meter station Determine the following: 1. Overhaul Volume 2. Length of Overhaul 3. Cost of Haul 4. Cost of Waste 5. Cost of BorrowCalculate the tender rate per bank cubic meter for an excavation of a trench given:• Hire cost = R800 per hour, including owning costs• Fuel Consumption = 4 l/h of Diesel fuel at R15/h• Scoop capacity is 35 banks m3/h• Operating factor = 0.8• Dimensions of trench: 10m x 3m• Operator earns R40.41/h• Head office overheads = 30%• Site overheads = 20%• Profit margin factor = 0.045• Contractor has perceived no risk on this operationChoose the lowest size and the required number of crawler hoes to excavate 828864 b-Cyd of sand & gravel in 4 months. A size one Cyd excavator (including the wage's operator) costs $80 /hr. with an increment of $5 per extra 0.5 Cyd. Depth of excavation 12 ft, Swell 25%, and efficiency 65%. Suppose the work is 8hr/day. Estimate the total expected cost.
- Calculate the cost per cubic yard to move earth for a project that plans to use a back-hoe and system of trucks. All equipment carries a rated heaped capacity, has a fill factor of 100%, and works 55-min hours. Back-hoe excavator costs are $105/hr (including operator), cycle time is 0.25 min, and bucket heaped capacity is 5.5 cy. Truck costs are $150/hr (including operator), dump time is 0.70 min (maneuver, dump, turn), heaped capacity is 32.5 cy, and 10 trucks are available for the project. Hauling equipment operates in one direction from A to B to C and finally to D according to the following table. Find the following values (note: carry out your calculations to at least 4 decimal points to obtain the best results): Section Load Length (ft) Speed (mph) full full A 2,800 2,400 2,900 2,800 в 18 empty empty 37 17Q1: In construction of a highway section, the earthwork information is available as shown in the table below. The free-haul distance is 500m and the swelling factor is 20%. Draw the mass haul diagram between station 3 + 00 and station 9 + 00 and determine the extra compensation that must be paid to the contractor when the overhaul price is $200/m3 station. Station Cut Fill 3 + 00 50 250 4 + 00 150 550 6+ 00 150 200 7+ 00 910 50 9 + 002. Determine the total cost of earthworks and draw the mass haul diagram of a highway section having the cumulative volume shown in the table below: Station No. ㅇ 5 9 13 15 Cumulative |Volume Given that cost of overhaul = Php 750.00/m²station, cost of borrow = Php 2500.00/m², cost of freehaul = Php 1250.00/m’, and the free haul distance = 9 stations. ㅇ 250 350 220 0 %3D %3D %3D %3D