Given the power series 00 2 A x(n + 3) n = 0 1. Force the Exponent "n + 3" to be "R" like we did in the last lesson.

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.1: Sequences And Series
Problem 9ECP: For the series i=1510i find (a) the fourth partial sum and (b) the sum. Notice in Example 9(b) that...
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Given the power series
00
Σ
E A x(n + 3)
n = 0
1. Force the Exponent "n + 3" to be "R" like we did in the last lesson.
2. Now use what we have learned in this lesson to force the new series to start at "R = 5".
00
00
A EA x(n + 3)
È (R - 3) A (R - 3) **
n = 0
R = 0
00
00
®E A, xu + 3) = E (R - 3) A, x*
Σ Α.xd+
B
n = 0
R = 1
00
Ž A, xle + 3) = E A (« - 3)
00
(R - 3)
n = 0
R = 0
Ο ΣΑ.
A, xla + 3)
A
*(R - 3) **
n = 0
R = -3
00
00
Θ Σ
(E
2 A x(m
g(n + 3) = E A, x*
n = 0
R = 0
00
Ž 4, xl* + *) = E A (R - 3) **
00
F
n = 0
R = 3
Transcribed Image Text:Given the power series 00 Σ E A x(n + 3) n = 0 1. Force the Exponent "n + 3" to be "R" like we did in the last lesson. 2. Now use what we have learned in this lesson to force the new series to start at "R = 5". 00 00 A EA x(n + 3) È (R - 3) A (R - 3) ** n = 0 R = 0 00 00 ®E A, xu + 3) = E (R - 3) A, x* Σ Α.xd+ B n = 0 R = 1 00 Ž A, xle + 3) = E A (« - 3) 00 (R - 3) n = 0 R = 0 Ο ΣΑ. A, xla + 3) A *(R - 3) ** n = 0 R = -3 00 00 Θ Σ (E 2 A x(m g(n + 3) = E A, x* n = 0 R = 0 00 Ž 4, xl* + *) = E A (R - 3) ** 00 F n = 0 R = 3
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