Given the power series 00 nA x(n - 1) n = 0 1. Force the Exponent "n - 1" to be "R" Ilike we did in the last lesson. 2. Now use what we have learned in this lesson to force the new series to start at "R = 2".

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 43E
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Given the power series
Σ
nA x(a - 1)
n = 0
1. Force the Exponent "n - 1" to be "R" Ilike we did in the last lesson.
2. Now use what we have learned in this lesson to force the new series to start at "R = 2".
00
A 2
x(n - 1)
Σ (R- 1)A,
n = 0
R
R = 0
00
B 2 n A x(u – 1)
2 RA, XR
R
n = 0
R = 1
00
© E n A x(n - 1) -
Ž (R - 1) A (R - 1) *
.R
n = 0
R = 1
00
n A x(" - 1) = E
+1) A (r + 1) **
n = 0
R = - 1
00
E 2 n A xu – 1)
2 RA, xR
R
n = 0
R = 0
00
6 2n A x(n – 1)
Ž (R + 1) A (R + 1) *
n = 0
R = 1
Transcribed Image Text:Given the power series Σ nA x(a - 1) n = 0 1. Force the Exponent "n - 1" to be "R" Ilike we did in the last lesson. 2. Now use what we have learned in this lesson to force the new series to start at "R = 2". 00 A 2 x(n - 1) Σ (R- 1)A, n = 0 R R = 0 00 B 2 n A x(u – 1) 2 RA, XR R n = 0 R = 1 00 © E n A x(n - 1) - Ž (R - 1) A (R - 1) * .R n = 0 R = 1 00 n A x(" - 1) = E +1) A (r + 1) ** n = 0 R = - 1 00 E 2 n A xu – 1) 2 RA, xR R n = 0 R = 0 00 6 2n A x(n – 1) Ž (R + 1) A (R + 1) * n = 0 R = 1
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