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Given the reaction of diamond converting to graphite 2C(s, diamond)→2C(s, graphite) a. Determine AG° at 298 K and determine if this reaction is spontaneous or not. b. What are the stable and metastable phases of carbon? Do we observe the conversion of diamond to graphite in real world? Justify your answer. AH° (C(s, diamond) = 1.9 kJ/mol ΔΗ° (C(s, graphite) = 0 kJ/mol So (C(s, diamond) = 2.38 J/(molK)

Given the reaction of diamond converting to graphite 2C(s, diamond)→2C(s, graphite) a. Determine AG° at 298 K and determine if this reaction is spontaneous or not. b. What are the stable and metastable phases of carbon? Do we observe the conversion of diamond to graphite in real world? Justify your answer. AH° (C(s, diamond) = 1.9 kJ/mol ΔΗ° (C(s, graphite) = 0 kJ/mol So (C(s, diamond) = 2.38 J/(molK)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Given the reaction of diamond converting to graphite 2C(s, diamond)→2C(s, graphite) a. Determine AG° at 298 K and determine if this reaction is spontaneous or not. b. What are the stable and metastable phases of carbon? Do we observe the conversion of diamond to graphite in real world? Justify your answer. ΔΗ° (C(s, diamond) 1.9 kJ/mol AH (C(s, graphite) So (C(s, diamond) = 2.38 J/(molK) Sᵒ (C(s, graphite)=5.74 J/(molK) = 0 kJ/mol
Transcribed Image Text:Given the reaction of diamond converting to graphite 2C(s, diamond)→2C(s, graphite) a. Determine AG° at 298 K and determine if this reaction is spontaneous or not. b. What are the stable and metastable phases of carbon? Do we observe the conversion of diamond to graphite in real world? Justify your answer. ΔΗ° (C(s, diamond) 1.9 kJ/mol AH (C(s, graphite) So (C(s, diamond) = 2.38 J/(molK) Sᵒ (C(s, graphite)=5.74 J/(molK) = 0 kJ/mol
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