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Given the system of inequalities below, determine the shape of the feasible region and find the vertices of the feasible region. Report your vertices starting with the one which has the smallest x-value. If more than one vertex has the same, smallest r-value, start with the one that has the smallest y-value. Proceed clockwise from the first vertex. Leave any unnecessary answer spaces blank. x + y< 9 5x + y > 13 x > 0 y > 0 The feasible region is The first vertex is ( ). The second vertex is ( The third vertex is ( The fourth vertex is ( ).

Given the system of inequalities below, determine the shape of the feasible region and find the vertices of the feasible region. Report your vertices starting with the one which has the smallest x-value. If more than one vertex has the same, smallest r-value, start with the one that has the smallest y-value. Proceed clockwise from the first vertex. Leave any unnecessary answer spaces blank. x + y< 9 5x + y > 13 x > 0 y > 0 The feasible region is The first vertex is ( ). The second vertex is ( The third vertex is ( The fourth vertex is ( ).

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter10: Inequalities
Section10.8: Systems Of Linear Inequalities
Problem 25WE
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Given the system of inequalities below, determine the shape of the feasible region and find the vertices of the feasible region. Report your vertices starting with the one which has the smallest x-value. If more than one vertex has the same, smallest x-value, start with the one that has the smallest y-value. Proceed clockwise from the first vertex. Leave any unnecessary answer spaces blank. x + y < 9 5x + y > 13 x > 0 y 2 0 The feasible region is The first vertex is ( ). The second vertex is ( ). The third vertex is ( ). The fourth vertex is ( ).
Transcribed Image Text:Given the system of inequalities below, determine the shape of the feasible region and find the vertices of the feasible region. Report your vertices starting with the one which has the smallest x-value. If more than one vertex has the same, smallest x-value, start with the one that has the smallest y-value. Proceed clockwise from the first vertex. Leave any unnecessary answer spaces blank. x + y < 9 5x + y > 13 x > 0 y 2 0 The feasible region is The first vertex is ( ). The second vertex is ( ). The third vertex is ( ). The fourth vertex is ( ).
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