Given the tables: emp [eid, ename, salary, d_id], depart [d_id, dname, manager_id] The result o the following two SQL statements are the same:
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![Given the tables: emp [eid, ename, salary, d_id], depart [d_id, dname, manager_id]
The result o the following two SQL statements are the same:
SQL1:
select name
from emp
where empid in (select manager_id
from depart):
SQL2:
select name
from emp e, depart d
where e.empid=d.manager_id;
Select one:
O True
O False](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F53d0d08e-2fd4-4f9c-8522-cd8cc0e548de%2Ff9d69630-4668-490b-af76-a9fdaadc3437%2F4yytrsc_processed.png&w=3840&q=75)
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- Consider the following two tables: Draw three tables that can result by executing each of the following SQL statements. . 1. SELECT c.Fname, c.Lname, c.email, o.orderDate, o.amount FROM Customers AS c INNER JOIN Orders AS o ON c. customerID = o. customerID; 2. SELECT c.Fname, c.Lname, c.email, o.orderDate, o.amount FROM Customers AS c LEFT OUTER JOIN Orders AS o ON c. customerID = o. customerID; 3. SELECT c.Fname, c.Lname, c.email, o.orderDate, o.amount FROM Customers AS c RIGHT OUTER JOIN Orders AS o ON c. customerID = o. customerID;For the following Relational Algebra / SQL statements, specify the output of each query. (do not explain how each query will be executed, but specify the output to be obtained when the query is executed). (c) R1: ACTORS WHERE YearOfBirth < 1940 OR Gender = 'female' R2(SSNo, FName, LName): R1 [ SSNo, FName, LName ] R3: R2 NATURAL-JOIN ACTEDIN OVER SSNo C: R3 [ LName, Character ] (d) SELECT A1.FName, A1.LName, A1.YearOfBirth FROM ACTORS A1, ACTORS A2 WHERE A1.YearOfBirth = A2.YearOfBirth AND A1.SSNo != A2.SSNo (e) R1: ACTEDIN [ FilmNo, SSNo ] R2: FILMS WHERE FilmTitle = 'Unforgiven' [ FilmNo ] R3: ACTEDIN NATURAL-JOIN R2 OVER FilmNo [ SSNo ] R4: ACTORS NATURAL-JOIN R3 OVER SSNo [ SSNo, FName, LName ] R5: ( R1.SSNo ÷ R4.SSNo ) [ FilmNo ] C: ACTEDIN NATURAL-JOIN R5 OVER FilmNo [ FilmTitle ] (f) SELECT A.FName, A.LName, COUNT(*) FROM ACTORS A, ACTEDIN AI WHERE A.SSNo = AI.SSNo GROUP BY A.SSNo, A.FName, A.LName HAVING count(*) > 2 OR count(*) = 02) Write SQL query that returns the Name of ALL employees (based on EMP_LNAME and EMP_FNAME in EMPLOYEE table, call this EMP_NAME), Gender of ALL employees (based on EMP_TITLE in EMPLOYEE table, call this EMP_NAME), and Pilot ratings if any (PIL_RATINGS in PILOT table). Output: EMP_NAME EMP_GENDER Rhett VanDam M John Lange M Jeanine Duzak F
- Given the following SQL query: Student (sid, name, age, address) Book (bid, title, author) Checkout (sid, bid, date) SELECT S.name FROM Student S, Book B, Checkout C WHERE S.sid = C.sid AND B.bid = C.bid AND B.author = ’Olden Fames’ AND S.age > 12 AND S.age < 20 Write relational algebra query for the above SQL query. Using a drawing tool such as Visio or others (ex: https://www.draw.io/ is a free one) to draw initial relational algebra query trees for the query generated in question 1. Transform the initial query trees created above into a more efficient form (use the heuristic rules and show your steps (.The following two SQL statements will produce the same results. SELECT P_DESCRIPT, P_PRICE FROM PRODUCT WHERE P_CODE IN (SELECT P_CODE FROM LINE GROUP BY P_CODE HAVING COUNT(*) >=1); SELECT P_DESCRIPT, P_PRICE FROM PRODUCT WHERE EXISTS (SELECT P_CODE FROM LINE WHERE LINE.P_CODE=PRODUCT.P_CODE); Group of answer choices A) True B) FalseThe following two SQL statements will produce the same results. SELECT P_DESCRIPT, P_QOH,P_PRICE FROM PRODUCT WHERE P_QOH >(SELECT P_QOH FROM PRODUCT WHERE P_CODE='11QER/31') AND P_PRICE>(SELECT P_PRICE FROM PRODUCT WHERE P_CODE='11QER/31'); SELECT P_DESCRIPT, P_QOH,P_PRICE FROM PRODUCT WHERE (P_QOH,P_PRICE) > (SELECT P_QOH,P_PRICE FROM PRODUCT WHERE P_CODE='11QER/31'); A) True B) False
- can you help me iwth these two queries in mySQL. Write a SQL statement to create a table job_history including columns employee_id, start_date, end_date, job_id and department_id and make sure that, the employee_id column does not contain any duplicate value at the time of insertion and the foreign key column job_id contain only those values which are exists in the jobs table. Write a SQL statement to create a table employees including columns employee_id, first_name, last_name, email, phone_number hire_date, job_id, salary, commission, manager_id and department_id and make sure that, the employee_id column does not contain any duplicate value at the time of insertion and the foreign key columns combined by department_id and manager_id columns contain only those unique combination values, which combinations are exists in the departments table.This question is related to SQL Fundamentals, Please son't answer using your handwriting From the Salesman and Customer tables below, write SQL statements to do the following: List the salesman id, rating and names of those salesmen who get rating from 3 to 5, sorted DESCENDING by rating. List all the customers’ information whose name starts with ‘F’ and the fourth character is ‘I’, rests may be any character. List the name and country of those customers and salesmen who belongs to the same country. Salesman table: p1 is attached Customer table: p22 is attached51. The given SQL statement is intended to either (1) list the customer numbers, customers names, and headquarter cities of customers headquartered in Los Angeles or (2) satisfy the two conditions of having a customer number higher than 1000 and being headquartered in Denver. SELECT CUSTNUM, CUSTNAME, HQCITY FROM CUSTOMER WHERE HQCITY= 'Los Angeles" Which set of lines should be added to the end of the statement to make the statement work as intended? A: (CUSTNUM>1000 AND HQCITY-'Denver'); B: AND (CUSTNUM>1000 AND HQCITY='Denver*); C:OR CUSTNUM>1000 OR HQCITY='Denver": D:OR (CUSTNUM> 1000 AND HQCITY='Denver*);
- Answer the given question with a proper explanation and step-by-step solution. sid name value working hours timestamp 14 temperatureΑΒΒ 47 20 11/10/22015 12:00:00 16 humidityBosch 51 200 11/11/22015 12:00:00 19 temperatureΑΒΒ 41 NULL 11/11/22015 12:00:00 20 temperatureΑΒΒ NULL 30 11/12/22015 12:00:00 Write sql statement that calculates the average temperature for the temperature sensor and it will be showed Write sql statement that will show all the fields of of the table in order not to have duplex values THE NULLS VALUES MUST BE EXCLUDED . PLEASE WRITE THE ANSWER IN PAPERIndicate for each of the following SQL statements, how many tuples would be returned if it was run on the table of Articles given above. 1. SELECT NUMBER FROM ARTICLES WHERE YEAR < 2019;2. SELECT DISTINCT NUMBER FROM ARTICLES WHERE YEAR < 2019;3. SELECT AVG(YEAR) FROM ARTICLES GROUP BY PUBLICATION;4. SELECT NUMBER FROM ARTICLES WHERE TITLE LIKE ‘%D’;Give the query graph of the following query, expressed in SQL; SELECT T_NAME, S_NAME FROM TEACHER, COURSE, STUDENT WHERE credit_hour=3 AND TEACHER.TNO= COURSE.CNO AND STUDENT.CNO = COURSE.CNO
