Given the vector function (1) = (e+→¹², 2√³+1, 4 arctan(1-1)), find the speed and the equation of the tangent line to this curve at t = 2, then graph the tangent line. Speed= i(t) =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.4: Plane Curves And Parametric Equations
Problem 33E
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Given the vector function r(t) = (e+²³, 2√1³ +1, 4 arctan(1 − 1) find the speed and the
equation of the tangent line to this curve at t = 2, then graph the tangent line.
Speed =
i(t) =
Transcribed Image Text:Given the vector function r(t) = (e+²³, 2√1³ +1, 4 arctan(1 − 1) find the speed and the equation of the tangent line to this curve at t = 2, then graph the tangent line. Speed = i(t) =
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