Given two points [a, f(a)] and [b. f(b)], the linear Lagrange polynomial f(x) that passes through these points is given by f₁(x) = x=b ƒ(a) + x-tf(b) a-b A f₁(x) = f(a) + O C f(b)-f(a) f(b) b-a f₁(x) = f(a) + f(b) b-a b- B x x-b f₁(x) = f(a) + f(b) x-a b-a a-b O D
Given two points [a, f(a)] and [b. f(b)], the linear Lagrange polynomial f(x) that passes through these points is given by f₁(x) = x=b ƒ(a) + x-tf(b) a-b A f₁(x) = f(a) + O C f(b)-f(a) f(b) b-a f₁(x) = f(a) + f(b) b-a b- B x x-b f₁(x) = f(a) + f(b) x-a b-a a-b O D
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.9: Properties Of Determinants
Problem 46E
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Question
![Given two points [a, f(a)] and [b. f(b)], the linear Lagrange
polynomial fi(x) that passes through these points is given by
f₁(x)=x-bf (a) + f(b)
x-a
a-b
O A
f₁(x) = f(a) +
C
f(b)-f(a) f(b)
b-a
f₁(x) = f(a) + f(b)
b-a
b-a
B
x
x-b
f₁(x) = f(a) + f(b)
x-a
b-a
a-b
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b88c2c9-5dd7-45bb-bc52-aa985c46d40b%2Fcf527504-0f27-4584-8ec4-6294ea10c17a%2Ff2c56hh_processed.png&w=3840&q=75)
Transcribed Image Text:Given two points [a, f(a)] and [b. f(b)], the linear Lagrange
polynomial fi(x) that passes through these points is given by
f₁(x)=x-bf (a) + f(b)
x-a
a-b
O A
f₁(x) = f(a) +
C
f(b)-f(a) f(b)
b-a
f₁(x) = f(a) + f(b)
b-a
b-a
B
x
x-b
f₁(x) = f(a) + f(b)
x-a
b-a
a-b
D
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