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A: Given question:- True or False?
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A: solution is given below
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A: Above question is solved.
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A: SOLUTION-
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- Find the area enclosed by one loop of this polar curve: r=3sqrt(cos2theta) from 0 to 2pi using the formula A=1/2 integral from 0 to 2pi (r)^2 for parametric curve.Use polar coordinates to integrate under z=xy above the first quadrant of the unit circle on the xy plane?Use Green’s theorem to evaluate 3 3C∫ y dx − x dy where C is the curve shown:where r1=3 and r2=5 units. Use polar coordinates to evaluate the resulting double integral.
- Find the area of the surface of revolution generated by revolving the curver = 2acos(theta) about the initial line.Evaluate ∫ ∫ √ (x2+ y2) dA where R is the portion of the annulus 1 ≤ x2 + y2 ≤ 16 with y ≤ 0 using polar coordinates.Find the area enclosed by the loop of this polar curve: r=4costheta-2sectheta from -pi/3 to pi/3 using the formula A= 1/2 integral from -pi/3 to pi/3 (r)^2 dtheta.