graph below, whet is a pont ad which it would O Giue the function in the reas ona ble estimete interect with its inverse. (b)(2, 3) ()3,3) (d) Not ehocesh intomgly

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Q: Answer

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A: We know, 2sin2A=1−cos2A  2cos2A=1+cos2A2cosAcosB=cos(A+B)+cos(A−B)

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A: Please see the answer below.

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A: Limits

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A: To evaluate: I=∫tan(2x) dx Substitute 2x=t⇒2dx=dt⇒dx=12dt: I=∫tan tdt2=12∫sin tcos tdt

Q: 3. Evaluate: lim ( ) X-0 sinx

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A: Solving

Q: please use the method of Miscellaneous Substitution

A: Here  We will use miscellaneous Substitution instead of partial fraction.

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Q: 323. Evaluate: J tanV |1 – x |dx 1 + x

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A: The given function is;  f(x)=x3+6x2+2.

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