is that true because I think the true answer (not one-to-one) ? 6:030.93 :4GKB/S4lu 23bartleby.com/que= bartlebyQ&AEngineering / Computer Scie... / Q&A Library / 1- ...1- Let f: R→R be a function defined ...TO eacli elemenL OI A.Step 2Answer:V Let F: R→R bea function defined as f(x) = (e+2)Solution:- As we know by the defination of one- to - oneFunction is:if we take F(ae) = f(x2) then if we prove that =2then function is one-to-one otherwise muny one,So, here F(x)= (x+2)²F(ei) = (x;+2)"Free) = (<2+2then5o, if we take,Fe) = F(x2):: Take under Root both, side., +2 = lz+2=) , +2-2=x2-)i. e., Civen function is one -to-one function.2) Verify that froe)= 5x-1 and gloæe)=cat)/5 areinverse function.Solution:-As weknow thatif F[ g(x>] =xAnd a[frx)] =xthen these Functions are inverse.detsFrx) = 5x-1and g(x)= *!T-

> Let F: R→R bea function defined as f(æ)= (x+2). Solution:- As we know by the defination of one-to - one Function is: if we take Frae) = F(x2) then if we prove that aG=H2 then function is one-to-one otherwise muny one, So, here F(x)= (x+2)? then F(ei) = (x,+2)? Frxx) = (Xz+2) 50, if we take, Frse;)= F(x2) (xi+2) = ((2+2? :: Take under Root both, side. %3D 2,+2 = H+2 =) o, +2-2=X2 -) i. e., Given function is one - to-one Function.

> Let F: R→R bea function defined as f(æ)= (x+2). Solution:- As we know by the defination of one-to - one Function is: if we take Frae) = F(x2) then if we prove that aG=H2 then function is one-to-one otherwise muny one, So, here F(x)= (x+2)? then F(ei) = (x,+2)? Frxx) = (Xz+2) 50, if we take, Frse;)= F(x2) (xi+2) = ((2+2? :: Take under Root both, side. %3D 2,+2 = H+2 =) o, +2-2=X2 -) i. e., Given function is one - to-one Function.

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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