gy is lost to the room t nt is 5.67 x 108 w/(m
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![A person steps out of the shower and dries off. The person's skin with an emissivity of 0.70 has a total area of 1.2 m2 and a
temperature of 33.2 °C. What is the net rate (in W) at which energy is lost to the room through radiation by the naked person
if the room temperature is 24.5 °C? The Stefan-Boltzmann constant is 5.67 x 10-8 WI(m2 · K4).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa055e27-0ea6-4923-acb6-78675f327ed1%2F728793f8-c522-41e8-8908-7a149f6db9a2%2Ftckcdm_processed.png&w=3840&q=75)
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