gy is lost to the room t nt is 5.67 x 108 w/(m

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A person steps out of the shower and dries off. The person's skin with an emissivity of 0.70 has a total area of 1.2 m2 and a
temperature of 33.2 °C. What is the net rate (in W) at which energy is lost to the room through radiation by the naked person
if the room temperature is 24.5 °C? The Stefan-Boltzmann constant is 5.67 x 10-8 WI(m2 · K4).
Transcribed Image Text:A person steps out of the shower and dries off. The person's skin with an emissivity of 0.70 has a total area of 1.2 m2 and a temperature of 33.2 °C. What is the net rate (in W) at which energy is lost to the room through radiation by the naked person if the room temperature is 24.5 °C? The Stefan-Boltzmann constant is 5.67 x 10-8 WI(m2 · K4).
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