h answer belongs to which option. Use only Multisim as a simulation. Thank you in advance for your complete answers.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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A, B, C answer options. Specify which answer belongs to which option. Use only Multisim as a simulation. Thank you in advance for your complete answers.
R1
R4
1kO
10ka
R2
10KO
R5
$2.7kO
Rload
1.8kO
v2
10V
V1
5V
IL
• VL-
R3
R6
$4.7kO
12 k2
Figure 3.1. Linear Circuit to Study Thevenin and Norton
A- Considering the circuit given in Figure 3.1, can RT be determined using only the given measurements?
How? Show and explain
(current IL = -379 uA and voltage across Rload VL = -681.489 V ) , Thevenins voltage Vth - -3.494 V)
B- Draw the Norton equivalent circuit using the appropriate data obtained from figure 3.1 below.
(Norton current= 469.846uA = -0.469.A , Thevenm resstence = 7.429kOhm)
R1
R4
1kO
10ko
R2
10KO
RS
3.30
Rload
1.8kO
V1
V2
b
+ VL-
R3
5.6k0
R6
4.7kO
Figure 3.3
C- Set up the circuit given in Figure 3.3 and find the Thevenin equivalent circuit seen by RLoad as per the
instructions (ie., the equivalent circuit between nodes A and B, RLoad deactivated).
a Set the 10kW potentiometer to the original load value and connect it between nodes A&B.
b. Vary the potentiometer to zero and measure the current IP through the potentiometer. (IP is the Norton
current (IN))
c. Remove the potentiometer from the circuit. Set all the voltage sources to zero volts, and use the
ohmmeter to measure the equivalent resistance between nodes A & B (This is the Norton Resistance=RN).
Transcribed Image Text:R1 R4 1kO 10ka R2 10KO R5 $2.7kO Rload 1.8kO v2 10V V1 5V IL • VL- R3 R6 $4.7kO 12 k2 Figure 3.1. Linear Circuit to Study Thevenin and Norton A- Considering the circuit given in Figure 3.1, can RT be determined using only the given measurements? How? Show and explain (current IL = -379 uA and voltage across Rload VL = -681.489 V ) , Thevenins voltage Vth - -3.494 V) B- Draw the Norton equivalent circuit using the appropriate data obtained from figure 3.1 below. (Norton current= 469.846uA = -0.469.A , Thevenm resstence = 7.429kOhm) R1 R4 1kO 10ko R2 10KO RS 3.30 Rload 1.8kO V1 V2 b + VL- R3 5.6k0 R6 4.7kO Figure 3.3 C- Set up the circuit given in Figure 3.3 and find the Thevenin equivalent circuit seen by RLoad as per the instructions (ie., the equivalent circuit between nodes A and B, RLoad deactivated). a Set the 10kW potentiometer to the original load value and connect it between nodes A&B. b. Vary the potentiometer to zero and measure the current IP through the potentiometer. (IP is the Norton current (IN)) c. Remove the potentiometer from the circuit. Set all the voltage sources to zero volts, and use the ohmmeter to measure the equivalent resistance between nodes A & B (This is the Norton Resistance=RN).
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