H n=e or 1 or 2 def divide (S): if SX 2 = e: return 'J=e elif (-1)^(-n) > 8: def fun(n): if S is range (2): how to code this in matlab if S is range (8): program? n=1 else: n2 return'Jneven' else: return'2=odd S-int (input( "Calculation of the Parity of the nucleos: ")) print (divide(5)) Calculation of the Parity of the nucleos:
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- Scrabble is a word game in which words are constructed from letter tiles, each letter tile containing a point value. The value of a word is the sum of each tile's points added to any points provided by the word's placement on the game board. Write a program using the given dictionary of letters and point values that takes a word as input and outputs the base total value of the word (before being put onto a board). Ex: If the input is: PYTHON the output is: 14 tile_dict = { 'A': 1, 'B': 3, 'C': 3, 'D': 2, 'E': 1, 'F': 4, 'G': 2, 'H': 4, 'I': 1, 'J': 8, 'K': 5, 'L': 1, 'M': 3, 'N': 1, 'O': 1, 'P': 3, 'Q': 10, 'R': 1, 'S': 1, 'T': 1, 'U': 1, 'V': 4, 'W': 4, 'X': 8, 'Y': 4, 'Z': 10 } ''' Type your code here. '''Brussel's choice def brussels_choice_step(n, mink, maxk): This problem is adapted from another jovial video "The Brussel's Choice" of Numberphile (a site so British that you just know there has to be a Trevor and a Colin somewhere in there) whose first five minutes you should watch to get an idea of what is going on. This function should compute and return the list of all numbers that the positive integer n can be converted to by treating it as a string and replacing some substring m of its digits with the new substring of either 2*m or m/2, the latter substitution allowed only when m is even so that dividing it by two produces an integer. This function should return the list of numbers that can be produced from n in a single step. To keep the results more manageable, we also impose an additional constraint that the number of digits in the chosen substring m must be between mink and maxk, inclusive. The returned list must contain the numbers in ascending sorted order.Python Scrabble is a word game in which words are constructed from letter tiles, each letter tile containing a point value. The value of a word is the sum of each tile's points added to any points provided by the word's placement on the game board. Write a program using the given dictionary of letters and point values that takes a word as input and outputs the base total value of the word (before being put onto a board). Ex: If the input is: PYTHON the output is: 14 part of the code: tile_dict = { 'A': 1, 'B': 3, 'C': 3, 'D': 2, 'E': 1, 'F': 4, 'G': 2, 'H': 4, 'I': 1, 'J': 8, 'K': 5, 'L': 1, 'M': 3, 'N': 1, 'O': 1, 'P': 3, 'Q': 10, 'R': 1, 'S': 1, 'T': 1, 'U': 1, 'V': 4, 'W': 4, 'X': 8, 'Y': 4, 'Z': 10 }
- in phython langauge: Write a program which reads the number of blocks the builders have,and outputs the height of the pyramids that can be built using these blocks.y(n) - 4y(n - 2) = 2x(n - 2) - 3x(n − 3) difference, with q(n) being the state variable vectorIf the equations of state of the system expressed by Eq.q(n + 1) = Aq(n) + Bx(n)y (n) = Cq (n) + Dx (n)1.II.103IV. 2Which one is an element of vector C?AOnly 11Bi velwithNoneDYalne IVANDHe ve IVThe sieve of Eratosthenes is a way of computing all the prime numbers below a certain number. (A prime number is a number that is only divisible by itself and 1). This algorithm is explained excellently in this video (Links to an external site.), or you can read about this ancient algorithm on Wikipedia (Links to an external site.). Implement this algorithm: Implement a function cross_out_multiples that takes as arguments a list of boolean values (true/false) called is_prime and a number n. The function sets the boolean values at all multiples of n (2*n, 3*n, 4*n ...) that are in the list to false. Implement a function sieve(n) which gives back a list of all primes below n. Needs to written in Python with the use of funtions and input parcers
- INT_MIN = -32767 def cut_rod(price): """ Returns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val return val[n] # Driver program to test above functionsarr = [1, 5, 8, 9, 10, 17, 17, 20].Sorting Jojo was given a Math assignment by his teacher. Jojo's task is to sort a number of given then find the closest pair of numbers that has the maximum difference after sorted. Jojo was asked to write down a list of the pairs of numbers. Input FormatThe first line of input is an integer N i.e. the number of numbersThe second line is a series of numbers Ai as many as N Output FormatPairs of numbers separated by spaces Constraints2 ≤ N ≤ 105-107 ≤ Ai ≤ 107 Sample Input 52 -8 3 1 -10 Sample Output-8 1 Sample Input1045 9 3 -6 100 68 -57 23 -11 -25 Sample Output-57 -25 68 100 In the sample above if the input is sorted then:-10 -8 1 2 3 so that the difference between each number in sequence is 2, 9, 1, 1-57 -25 -11 -6 3 9 23 45 68 100 so the difference is 32, 14, 5, 9, 6, 14, 22, 23, 32 NotesEven though it wasn't stated in the problem, by now you should know that the advantages spaces or lines are considered WRONG ANSWER.Exercise Fibonacci (Overflow): Write a program called FibonacciInt to list all the Fibonacci numbers, which can be expressed as an int (i.e., 32-bit signed integer in the range of [-2147483648, 2147483647]). The output shall look like: F(0) = 1 F(1) = 1 F(2) = 2 ... F(45) = 1836311903 F(46) is out of the range of int Hints: The maximum 32-bit int is kept in constant Integer.MAX_VALUE. You cannot use F(n-1) + F(n-2) > Integer.MAX_VALUE to check for overflow. Instead, overflow occurs for F(n) if (Integer.MAX_VALUE – F(n-1)) < F(n-2), i.e., no room for the next number. Try: Write a similar program for Tribonacci numbers. Exercise NumberConversion: Write a method call toRadix() which converts a positive integer from one radix into another. The method has the following header: public static String toRadix(String in, int inRadix, int outRadix) // The input and output are treated as String. Write a program called NumberConversion, which prompts the user for an input number, an input…
- Returns the missing number from a sequence of unique integers in range [0..n] in O(n) time and space. The difference between consecutive integers cannot be more than 1. If the sequence is already complete, the next integer in the sequence will be returned. For example: Input: nums = [4, 1, 3, 0, 6, 5, 2] Output: 7 """ def find_missing_number(nums): missing=0 fori, numinenumerate(nums): missing ^= num missing ^= i+1 returnmissing .8.27 LAB: Scrabble points Scrabble is a word game in which words are constructed from letter tiles, each letter tile containing a point value. The value of a word is the sum of each tile's points added to any points provided by the word's placement on the game board. Write a program using the given dictionary of letters and point values that takes a word as input and outputs the base total value of the word (before being put onto a board). Ex: If the input is: PYTHON the output is: 14 python tile_dict = { 'A': 1, 'B': 3, 'C': 3, 'D': 2, 'E': 1, 'F': 4, 'G': 2, 'H': 4, 'I': 1, 'J': 8, 'K': 5, 'L': 1, 'M': 3, 'N': 1, 'O': 1, 'P': 3, 'Q': 10, 'R': 1, 'S': 1, 'T': 1, 'U': 1, 'V': 4, 'W': 4, 'X': 8, 'Y': 4, 'Z': 10 }briefly comment the code#include <stdio.h>#include <stdlib.h>/* ADJACENCY MATRIX int source,V,E,time,visited[20],G[20][20];void DFS(int i){int j;visited[i]=1;printf(" %d->",i+1);for(j=0;j<V;j++){if(G[i][j]==1&&visited[j]==0)DFS(j);}}int main(){int i,j,v1,v2;printf("\t\t\tGraphs\n");printf("Enter the no of edges:");scanf("%d",&E);printf("Enter the no of vertices:");scanf("%d",&V);for(i=0;i<V;i++){for(j=0;j<V;j++)G[i][j]=0;}/* creating edges :P */for(i=0;i<E;i++){printf("Enter the edges (format: V1 V2) : ");scanf("%d%d",&v1,&v2);G[v1-1][v2-1]=1; } for(i=0;i<V;i++){for(j=0;j<V;j++)printf(" %d ",G[i][j]);printf("\n");}printf("Enter the source: ");scanf("%d",&source);DFS(source-1);return 0;}