[х + у х— 1. If 1=k , solve for the values of x, y, and z Lx — у [12 6 9. -
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![[х + у х —z
Lx – y
-1= al, solve for the values of x, y, and z
[12 7]
6
1. If
Га + 2b 2а — bi
2 [a + 2b 2a – b] = [4 -4, find a, b, c and d.
2. If
12с + d с - 2d
|
14
|
[a
3. If
and c = a – 2b +d , find x
4
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- Prove that equation 2x ^2 y - y^3 + xz^2 = 40 has a positive integer solution. Prove byfinding one such solution.11. Solve by the substitution method. (If there is no solution, enter NO SOLUTION. Use the parameters x and y as necessary.) 6x - 4y = 18 3x - 2y = 15 (x, y) = _______Find the wrong Kian W(y1,y2)(t) of y1 and y2 Where y1=t and y2= e^t are solutions of (1-t)y"+ty'-y=0
- use the method of elimination to find the general solution for x(t) then y(t). Need only handwritten solution only (not typed one).When you plug in (0,0,0) into 7x - 5y + z = 0. It holds true, however, when you plug in (1,1,1) into 5x - 4y + 2z = 3, shouldn't the answer come out to be 0? Which verifies the problem. I tried it myself and got pi2 is equal to x + y -4z + 2 = 0 but Don't know if it's right.1. Solve using Gauss Jordan Elimination Method. Compute also for x, y and z.
- 1. Use the Gaussian Elimination method to solve:•1x + 2y + 3z = 14•2x + 1y + 3z = 13•2x + 3y + 1z = 112) Solve using the Gauss-Jordan Method. X+ y =−1 2x−y+z= 6 3x+2z=7 3) Given that p= (1 -1 3 2) Use p-1 to solve the simultaneous equations X−y= −5 3x+2y=−5Explain why an equation Ax = b has a solution if and only if b is orthogonal to all solutions of the equation ATx =0.