(h) Yk+1 – Yk = kek,

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 47RE
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Solve the determine

Section 2.2
2.1. Solve the following difference equations:
(a) Yk+1+ Yk = 2+ k,
(b) Ук+1
2yk = k3,
3* yk = 0,
(c) Yk+1
(d) Yk+1 – Yk = 1/k(k+1),
(e) Yk+1 + Yk = 1/k(k+1),
(f) (k + 2)yk+1 – (k + 1)yk = 5 + 2* – k²,
(g) Yk+1 + Yk = k + 2 · 3k,
(h) Yk+1 –
- Yk = ke*,
Bak,
(i) Ук+1
og2k,
Yk =
(j) Yk+1 – ayk = cos(bk),
Transcribed Image Text:Section 2.2 2.1. Solve the following difference equations: (a) Yk+1+ Yk = 2+ k, (b) Ук+1 2yk = k3, 3* yk = 0, (c) Yk+1 (d) Yk+1 – Yk = 1/k(k+1), (e) Yk+1 + Yk = 1/k(k+1), (f) (k + 2)yk+1 – (k + 1)yk = 5 + 2* – k², (g) Yk+1 + Yk = k + 2 · 3k, (h) Yk+1 – - Yk = ke*, Bak, (i) Ук+1 og2k, Yk = (j) Yk+1 – ayk = cos(bk),
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