(х — Зу + 2)dx + 3(х + 3у — 4)dy —D 0 x-1 a. In[(x – 1)2 – 9(y – 1)²] – Arctan C 3 (у-1) | x-1 b. In[(x – 1)? + 9(y – 1)²] – Arctan C | (y-1) х-1 c. In[(x – 1)2 +9(y – 1)²] – Arctan C 3(у-1) у-1 d. In[(x – 1)² +9(y – 1)²] – Arctan 3(х-1) e. None of the above
(х — Зу + 2)dx + 3(х + 3у — 4)dy —D 0 x-1 a. In[(x – 1)2 – 9(y – 1)²] – Arctan C 3 (у-1) | x-1 b. In[(x – 1)? + 9(y – 1)²] – Arctan C | (y-1) х-1 c. In[(x – 1)2 +9(y – 1)²] – Arctan C 3(у-1) у-1 d. In[(x – 1)² +9(y – 1)²] – Arctan 3(х-1) e. None of the above
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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Question
Find the differential equation of this equation (Please provide a complete solution)
Solve this equation using the Coefficient in Linear of 2
![(х — Зу + 2)dx + 3(х + 3у — 4)dy 3D 0
х-1
a. In[(x – 1)2 – 9(y – 1)²] – Arctan
= C
3(y-1)
x-1
b. In[(x – 1)2 + 9(y – 1)²] – Arctan
C
(y-1)
х-1
c. In[(x – 1)2 + 9(y – 1)²] – Arctan
= C
3(y-1)
= C
d. In[(x – 1)2 + 9(y – 1)²] – Arctan -1
3 (х-1)
|
|
e. None of the above](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc3126407-0add-4dd2-8a2f-57b3ccfcef4d%2F3ab4f4d9-f46f-453f-b279-3aad3d62beb9%2Fs6v5ubw_processed.png&w=3840&q=75)
Transcribed Image Text:(х — Зу + 2)dx + 3(х + 3у — 4)dy 3D 0
х-1
a. In[(x – 1)2 – 9(y – 1)²] – Arctan
= C
3(y-1)
x-1
b. In[(x – 1)2 + 9(y – 1)²] – Arctan
C
(y-1)
х-1
c. In[(x – 1)2 + 9(y – 1)²] – Arctan
= C
3(y-1)
= C
d. In[(x – 1)2 + 9(y – 1)²] – Arctan -1
3 (х-1)
|
|
e. None of the above
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