h. z = tan (/Zn + Ze ) i. z = csc ( Za – Za)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.4: Multiple-angle Formulas
Problem 29E
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Topic: Trigonometric functions of complex number Instruction: Express your answer in rectangular form, 3 decimal places.
Given:
Za = -2 – 5i
Zp = 2.15 e4.18i
Z. = 1.75 (cos165° + į sin165°)
Za = 0.745/-36°
Ze = 1+ 3i
Zf = 0.953 (cos324° + į sin324°)
2.32/75°
1.18 eni
Transcribed Image Text:Given: Za = -2 – 5i Zp = 2.15 e4.18i Z. = 1.75 (cos165° + į sin165°) Za = 0.745/-36° Ze = 1+ 3i Zf = 0.953 (cos324° + į sin324°) 2.32/75° 1.18 eni
h. z = tan
(JZn + Ze )
i. z = csc ( Za – Za)
Transcribed Image Text:h. z = tan (JZn + Ze ) i. z = csc ( Za – Za)
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