H.W2: Consider the circuit i. Find: (a) Leg, 1(t) and i2(t) if i, = e-t mA (b) Vo(t) (c) energy stored in the 20-mH inductor at t = 1 s. 4 mH 20 mH 6 mH
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- Q2: In a dielectric material (ɛ = 5ɛ, ), the potential field V= 10xyz - 5z? V, determine (a) E, (b) D, (c) P, (d) P.6. Given the function F = [I(0, 1, 4, 6, 7,8,9) + Md(5, 10, 11,12) a. [10] Write the equation for F in reduced SOP form b. [10] Draw the circuit using AND gates, OR gates and INVERTERS. 0 c. [10] Draw the circuit using only NAND gates and INVERTERS.6. Given the function F = [I(0, 1, 4,6, 7,8,9) + Md(5,10, 11, 12) a. [10] Write the equation for F in reduced SOP form b. [10] Draw the circuit using AND gates, OR gates and INVERTERS.
- Find the impedance theoretically of a wire if it carries the frequency 10 kHz have a voltage is 8v, the current is 2mA, resistance is 13 k, inductance 29 mH and capacitance 0.1 ufLogic Function F (x, y, z, w) = ∑ m (0,2,4,6,10,13) + ∑ k (8,12) as sum of minimers are given. (Note: There are terms that are not taken into account.) a. Obtain the Truth Table. b. Simplify with the Karnough Map approach. c. Draw the simplified Logic circuit with two input AND-NOT (NAND) gates. With how many apples you realized, what is your gain? Comment.3. Given BF is F(x,y,z) = x yz +xyz+ ï ỹž+xỹz. (i) Simplify the BF by k-map (ii) Draw a circuit(using inverter, OR, AND gates) and make a truth table of simplified form of BF.
- a) Draw the simplified hazard-free circuit of F(A,B,C,D,E)=E(4,6,20,22,28,29)Q1: The following Boolean function Y=fA,B,C,D,E,F) =Em (0,5,7,8,9,12,13,23,24,25,28,29,37,40,42,44,46,55,56,57,60,61) Design the function with minimal logic gates using Karnaugh Map Method.Example 2: calculate the RMS noise voltage arising from thermal noise in two resistors 100 & 150 resp. at T= 300°K within a bandwidth of IMHZ if: a- The resistors are connected in series. b- The resistors are connected in parallel.
- Find a Hamiltonian circuit inCay({(a, 0), (b, 0), (e, 1)}:Q4 ⊕ Z2).3. You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd order differential equation where we solved for the current. This time we will use an even simpler concept: principle of conservation of energy to derive the 2nd order differential equation where we will solve for the charge. Take a look at the circuit below. IHE 2F In the circuit above, we have a capacitor with capacitance 2 F, an inductor of inductance 5 H and a resistor of 32 (a) The total energy that is supplied to the resistor is LI? E = 2 Q? 20 where L is the inductance, I is the current, C is the capacitance and Q is the charge. Write down the total energy supplied E in terms of Q and t only. OP Remember that I = dt (b) Now you know that the power dissipation through a resistor is -1R. Use the conservation of energy (energy gain rate = energy loss rate) to derive the differential equation in terms Q and t only. (c) Solve the differential equation for initial charge to be Qo with a initial current of…Q2: The following Boolean function Y=f(A.B.C,D,E) = Em (0,1,4,5,16,17,21,23,25,29)+d(7,27,31) Design the function with minimal logic gates and simplify the functions Using Karnaugh Map Method.