х3 — Зх2 + 5 f (x) = х3 + 1

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
ChapterP: Prerequisites
SectionP.3: Polynomials And Special Products
Problem 8ECP: Find the product of x2+3y and x23y.
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For the given equation, find all concave up and concave down intervals.

x3 – 3x2 + 5
f (x) =
x3 + 1
Transcribed Image Text:x3 – 3x2 + 5 f (x) = x3 + 1
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