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What ratio of
phenotype of f1 progeny : BbWw
f1 siblings : BBWW, BBww, BbWw, BbWW, Bbww, bbWw,
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- In genetics, the dash symbol (–) is a “wild card” that stands for either the dominant allele or the recessive allele; for example, A– means the individual has either the genotype AA or Aa. Two genes that undergo independent assortment affect coat color in Duroc pigs. Each gene has two alleles, one of which is dominant for coat color. Genotypes of the form A– B– are red, those of the form A– bb and aa B– are sandy, and genotype aa bb is white. What ratio of red:sandy:white is expected from the cross Aa Bb x Aa Bb?The allele b gives Drosophila flies a black body and b+ gives brown, the wild-type phenotype. The allele wx of a separate gene gives waxy wings and wx+ gives non-waxy, the wild-type phenotype. The allele cn of a third gene gives cinnabar eyes and cn+ gives red, the wild-type phenotype. A female heterozygous for these three genes is testcrossed, and 1000 progeny are classified with the following phenotypes. 382 cinnabar 379 black, waxy 69 waxy, cinnabar 67 black 48 waxy 44 black, cinnabar 5 wild type 6 black, waxy, cinnabar Based on this data, what is the correct map of these genes in terms of order and distance?A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous for both of these recessive traits. The following data was produced from the cross. Test these data to determine if they are significantly different from the expected phenotypic ratio. Remember to use the 5% level of significance Wild eye Wild body – 102, Wild eye Ebony body – 94, Sepia eye Wild body – 100, Sepia eye Ebony body – 93. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject.
- In a species of plant, two genes control flower color. The red allele(R) is dominant to the white allele (r); the color-producing allele(C) is dominant to the non-color-producing allele (c). You suspectthat either an rr homozygote or a cc homozygote will producewhite flowers. In other words, rr is epistatic to C, and cc is epistatic to R. To test your hypothesis, you allow heterozygous plants(RrCc) to self-fertilize and count the offspring. You obtain the following data: 201 plants with red flowers and 144 with white flowers. Conduct a chi square analysis to see if your observed data areconsistent with your hypothesis.A genetic engineer is going to cross two watermelon plants to produce seeds for a spring planting. He is breeding for size, and wants to have as many watermelons with the phenotype for long shape as possible. In watermelons, the allele for short shape (R) is dominant to the allele for long shape (r). Would crossing a watermelon homozygous recessive for the trait with a watermelon heterozygous for the trait give the most long watermelons possible? Explain your answer using Punnett Squares.You have been tasked by a pharmaceutical company to generate a novel strain of Cannabis sativa for therapeutic purposes. Consider a Cannabis strain with three genes (called gene 1, gene 2 and gene 3) that are on different chromosomes and assort independently. Each gene has two alleles, described below: The T allele for gene 1 is dominant and associated with the trait of producing large amounts of terpenes, and the t allele is recessive and associated with the trait of producing a low amount of terpenes The S allele for gene 2 is dominant and associated with the trait of fast growth, and the s allele is associated with the trait of slow growth The F allele for gene 3 is associated with the trait of producing large flowers, and the f allele is associated with the trait of producing small flowers Assume that an individual plant that is heterozygous for genes 1 and 2, but homozygous ff for gene 3 self-fertilizes. What is the probability of getting a plant that produces a large number of…
- You are doing a genetics experiment with the fruit fly. In the “P” generation, you cross two true-breeding flies. The female parent is brown and wingless and the male parent is black with normal wings. All of the flies in the F1 generation are brown and have normal wings. Assume the genes are not found on a sex chromosome. Indicate the body color alleles with B and b and the wing size alleles with N and n. a) The genotypes of the flies in the P generation are: Female: ______________ Male: ______________ b) The genotype of the flies in the F1 generation is: _____________ c) You now take an F1 female and cross her to a true-breeding black, wingless male. This male’s genotype is: ______________You have been tasked by a pharmaceutical company to generate a novel strain of Cannabis sativa for therapeutic purposes. Consider a Cannabis strain with three genes (called gene 1, gene 2 and gene 3) that are on different chromosomes and assort independently. Each gene has two alleles, described below: The T allele for gene 1 is dominant and associated with the trait of producing a large amounts of terpenes, and the t allele is recessive and associated with the trait of producing a low amount of terpenes The S allele for gene 2 is dominant and associated with the trait of fast growth, and the s allele is associated with the trait of slow growth The F allele for gene 3 is associated with the trait of producing large flowers, and the f allele is associated with the trait of producing small flowers Assume that an individual plant that is heterozygous for genes 1 and 2, but homozygous ff for gene 3 self-fertilizes. What is the probability of getting a plant that produces a large amount…As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! Review the information on Labrador retrievers above. What are the phenotypic ratios of the F1 generation offspring of two dihybrids? Make sure to match the numbers with coat colors (e.g, which number in the ration goes with which color). Use a Punnett square to…
- As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! 1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.Two true breeding plants are cross pollinated. One plant is homozygous dominant for heightand color while the other is homozygous recessive for height and color. (A:tall, a:short, B:brown,b:red) The F1 plants are allowed to self-fertilize to produce an F2 generation. After conductingan experiment we get the following results:398 tall and brown plants122 tall and red plants128 short and brown plants45 short and red plants Using the Chi Square formula and table, determine if your results support the hypothesis ofindependent assortment or not. Show your work. You don’t need to show your Punnett Squaresif you include a statement as to how you figured out the appropriate phenotypic ratio for the F2generation. Round to 1 decimal.4a. What possible gametes can the following individual make: AaBb4b. What possible gametes can the following individual make: AaBbCCWhen many families were tested for the ability to tastethe chemical phenylthiocarbamide, the matings weregrouped into three types and the progeny were totaled,with the results shown below:ChildrenNumber NonParents of families Tasters tastersTaster × taster 425 929 130Taster × nontaster 289 483 278Nontaster × nontaster 86 5 218With the assumption that PTC tasting is dominant (P)and nontasting is recessive (p), how can the progenyratios in each of the three types of mating be accountedfor?