Solve the given problem using the equation of Combined gas law.1. Helium gas has a volume of 250 mL at 273Kat 1.0 atm. What will be the final pressure ( P2 ) if the volumeis reduced to 100 mL at 318K?2. The volume of a gas at 270C and 700.0 mmHg is 600mL.What is the final volume ( V2 ) of the gas at -200Cand 500.0 mmHg? COMBINED GAS LAW states that the pressure and volume of a gas are inversely proportional to each other, butare both_directly proportional to the temperature of that gas. In equation,P: V1 +T1 = P2 V2+T2Sample Problem:1. A 2.5L of nitrogen gas exerts a pressure of 760 torr at 473 K. What temperature is ( T2 ) needed to reducethe volume of 1.75 L at 1140 torr?Given : V1 = 2.5L P: = 760 torr T1 = 473 K V2 = 1.75LFormula : T2 = V2 P2T1 + V1 P1Solution : T2 = (1.75 L) (1140 torr)( 473 K) + (2.5 L) (760 torr )Answer : T2 = 497 KP2 = 1140 torr Unknown: T2 = ?

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Helium gas has a volume of 250 mL at 273Kat 1.0 atm. What will be the final pressure ( P2 ) if the volume is reduced to 100 mL at 318K?

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Question

Solve the given problem using the equation of Combined gas law.

1. Helium gas has a volume of 250 mL at 273Kat 1.0 atm. What will be the final pressure ( P2 ) if the volume
is reduced to 100 mL at 318K?
2. The volume of a gas at 270C and 700.0 mmHg is 600mL.What is the final volume ( V2 ) of the gas at -200C
and 500.0 mmHg?

COMBINED GAS LAW states that the pressure and volume of a gas are inversely proportional to each other, but
are both_directly proportional to the temperature of that gas. In equation,
P: V1 +T1 = P2 V2+T2
Sample Problem:
1. A 2.5L of nitrogen gas exerts a pressure of 760 torr at 473 K. What temperature is ( T2 ) needed to reduce
the volume of 1.75 L at 1140 torr?
Given : V1 = 2.5L P: = 760 torr T1 = 473 K V2 = 1.75L
Formula : T2 = V2 P2T1 + V1 P1
Solution : T2 = (1.75 L) (1140 torr)( 473 K) + (2.5 L) (760 torr )
Answer : T2 = 497 K
P2 = 1140 torr Unknown: T2 = ?

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