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Hello I am working on applications of inetgration, specifcally, surface area problems. I am currently stuck on the problem attached. I got to the part of (4 *  ∫secθ/(tanθ-4) * dθ) and not sure how to proceed after that.

Hello I am working on applications of inetgration, specifcally, surface area problems. I am currently stuck on the problem attached. I got to the part of (4 *  ∫secθ/(tanθ-4) * dθ) and not sure how to proceed after that.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hello I am working on applications of inetgration, specifcally, surface area problems. I am currently stuck on the problem attached. I got to the part of (4 *  ∫secθ/(tanθ-4) * dθ) and not sure how to proceed after that.

Set up an integral for the area of the surface obtained by rotating the given curve about the specified axis. - xy4y² 1, 1 ≤ y ≤ 5; x-axis dy
Transcribed Image Text:Set up an integral for the area of the surface obtained by rotating the given curve about the specified axis. - xy4y² 1, 1 ≤ y ≤ 5; x-axis dy
is 5) Ky = "y²-1, 12 y≤5 AST X-AIS x = 4y- - x = Y + y 2 1+ (4+ y2)² 1-764 2 S SA = 2144-3)² dy fy કેન્દ્ર du = = = dy du-Zy³=dy 124 2 4-5 4=141 4-5 BP: H+LYWE -4 人 u√1+ (4+2) 2 1+(4+00) 2 0 4 S 12 25 dv→ 45 VETANG July T 75 4+4 du 11+ (4+4)² 1 25 4+4 du иличног 4+ 25 42 D +11+ (4th)² JIF (44) + 4+0 du лично 25 V=44 dvecti ax 24 पाकार 4 (4+)(1) 211-14+57) (1+ SINCE= 2TAN (1 14 TANY (3) cos (w) = 1-TAN² (4) ས། 25 v=4+4 → u-v-4 drade -415565 44 Sice SECO IG TANG-Y t=TAN() 3 2+ cesta)= 1-t²
Transcribed Image Text:is 5) Ky = "y²-1, 12 y≤5 AST X-AIS x = 4y- - x = Y + y 2 1+ (4+ y2)² 1-764 2 S SA = 2144-3)² dy fy કેન્દ્ર du = = = dy du-Zy³=dy 124 2 4-5 4=141 4-5 BP: H+LYWE -4 人 u√1+ (4+2) 2 1+(4+00) 2 0 4 S 12 25 dv→ 45 VETANG July T 75 4+4 du 11+ (4+4)² 1 25 4+4 du иличног 4+ 25 42 D +11+ (4th)² JIF (44) + 4+0 du лично 25 V=44 dvecti ax 24 पाकार 4 (4+)(1) 211-14+57) (1+ SINCE= 2TAN (1 14 TANY (3) cos (w) = 1-TAN² (4) ས། 25 v=4+4 → u-v-4 drade -415565 44 Sice SECO IG TANG-Y t=TAN() 3 2+ cesta)= 1-t²
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