The circuit illustrated has a transistor with a VBEact = 0.7 V and a ß =100. It is assumed that is 0 V and VBIAS is 1 V. V CEsat 1. What is the minimum value for input voltage (V;) that will prevent the transistor from cut-off? Note the value should be negative 2. What is the maximum value for input voltage (V₁) that will prevent the transistor from saturation? Note the value should be positive 3. To achieve equivalent magnitudes of the answers in the solutions for questions 1 and 2, what adjustment should be made to the value of VBIAS. 4. To what extent/factors are variations in the input voltage (Vi) amplified at the output voltage (V)
The circuit illustrated has a transistor with a VBEact = 0.7 V and a ß =100. It is assumed that is 0 V and VBIAS is 1 V. V CEsat 1. What is the minimum value for input voltage (V;) that will prevent the transistor from cut-off? Note the value should be negative 2. What is the maximum value for input voltage (V₁) that will prevent the transistor from saturation? Note the value should be positive 3. To achieve equivalent magnitudes of the answers in the solutions for questions 1 and 2, what adjustment should be made to the value of VBIAS. 4. To what extent/factors are variations in the input voltage (Vi) amplified at the output voltage (V)
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter12: Electronic Control Devices
Section: Chapter Questions
Problem 3RQ: Diodes and rectifiers allow current to _________.
flow in one direction only
flow in both...
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Step 1: Given that
VIEWStep 2: 1) Calculation of minimum voltage of vi to prevent the transistor from cutoff
VIEWStep 3: 2) Calculation of the maximum voltage of vi to prevent the transistor from saturation mode
VIEWStep 4: 3) Adjustment in VBIAS to achieve the given requirement in part (1) and part (2)
VIEWStep 5: 3) DC analysis of the amplifier
VIEWStep 6: Calculation of voltage gain of the amplifier
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Hello! I just wanted to ask how did you get VT = 26m in the Emitter dynamic resistance in step 5? Also in step 6, is the KVL in Vi wrong? since Vi = -(IBR10k + IBBre) which makes Vo/Vi = (1k)(100) / -(86700+867) = -1.14
Av = -1.14
Hoping for your response. Thank you!
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