Here's a CFG, called PY, representing a small Python-like language: (STMTS)→(STMT) (STMTS)| (STMT) (STMT)→(ID) = (EXPR) | if (EXPR) : (STMT) else: (STMT) | print ((EXPR))|(EXPR) (EXPRS)→(EXPR), (EXPRS) | (EXPR) | ɛ (EXPR)→(ID)|(NUM)|(EXPR) == (EXPR) | (EXPR) + (EXPR) |(TUP) | lambda ( (IDS)) : (EXPR)|(ID) ((EXPRS) ) (TUP)→| ((EXPRS)) (NUM)→0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 (IDS)→(ID), (IDS)|(ID) | ɛ (ID)→a | b | c | ... | x | y | z (Yes, real-world languages are much more complicated than textbook examples.) The variables of the CFG are all the names enclosed in angle brackets, e.g., (EXPR) is a variable name. All other symbols used in the rules are terminals. Note, however, that unlike Python, this grammar ignores whitespace (so your answers to this problem do not need to explicitly deal with whitespace). 1. Give two strings in PY's language by showing their derivation steps. Each given string must have at least five derivation steps (and cannot be the strings in part 3).

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Here's a CFG, called PY, representing a small Python-like language:
(STMTS)→(STMT) (STMTS)| (STMT)
(STMT)→(ID) = (EXPR) | if (EXPR): (STMT) else: (STMT)
print((EXPR))| (EXPR)
(EXPRS)→(EXPR),(EXPRS) | (EXPR) | ε
(EXPR)→(ID)|(NUM)|(EXPR):
(EXPR)| (EXPR) + (EXPR)
| (TUP) | lambda ( (IDS)) : (EXPR) | (ID) ((EXPRS) )
==
(TUP)→| ((EXPRS))
(NUM)→0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
(IDS)→(ID), (IDS)| (ID) | ɛ
(ID)→a | b | c | · · · | x | y | z
(Yes, real-world languages are much more complicated than textbook examples.)
The variables of the CFG are all the names enclosed in angle brackets, e.g., (EXPR) is a
variable name. All other symbols used in the rules are terminals.
Note, however, that unlike Python, this grammar ignores whitespace (so your answers to
this problem do not need to explicitly deal with whitespace).
1. Give two strings in PY's language by showing their derivation steps. Each given string
must have at least five derivation steps (and cannot be the strings in part 3).
Transcribed Image Text:Here's a CFG, called PY, representing a small Python-like language: (STMTS)→(STMT) (STMTS)| (STMT) (STMT)→(ID) = (EXPR) | if (EXPR): (STMT) else: (STMT) print((EXPR))| (EXPR) (EXPRS)→(EXPR),(EXPRS) | (EXPR) | ε (EXPR)→(ID)|(NUM)|(EXPR): (EXPR)| (EXPR) + (EXPR) | (TUP) | lambda ( (IDS)) : (EXPR) | (ID) ((EXPRS) ) == (TUP)→| ((EXPRS)) (NUM)→0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 (IDS)→(ID), (IDS)| (ID) | ɛ (ID)→a | b | c | · · · | x | y | z (Yes, real-world languages are much more complicated than textbook examples.) The variables of the CFG are all the names enclosed in angle brackets, e.g., (EXPR) is a variable name. All other symbols used in the rules are terminals. Note, however, that unlike Python, this grammar ignores whitespace (so your answers to this problem do not need to explicitly deal with whitespace). 1. Give two strings in PY's language by showing their derivation steps. Each given string must have at least five derivation steps (and cannot be the strings in part 3).
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