heres the question:A 100- m steel tape is used to measure the distance of the line and found to be 1539.28 m long. During measurement, the tape is supported the ends under a pull of 10 kg and the observed mean temperature is 31 deg. celsius. The tape is of standard temperature of 20 deg. celsius and a tension of 12 kg. The cross sectional area of the tape is 0.035 sq. cm. The coefficient of linear expansion is 0.0000116/ deg. celsius and the modulus of elasticity of steel is 2.0 x 106 kg/ sq. cm. The tape weighs 1.5kg.

Residential Construction Academy: House Wiring (MindTap Course List)
5th Edition
ISBN:9781337402415
Author:Gregory W Fletcher
Publisher:Gregory W Fletcher
Chapter11: Cable Installation
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heres the question:A 100- m steel tape is used to measure the distance of the line and found to be 1539.28 m long. During measurement, the tape is supported the ends under a pull of 10 kg and the observed mean temperature is 31 deg. celsius. The tape is of standard temperature of 20 deg. celsius and a tension of 12 kg. The cross sectional area of the tape is 0.035 sq. cm. The coefficient of linear expansion is 0.0000116/ deg. celsius and the modulus of elasticity of steel is 2.0 x 106 kg/ sq. cm. The tape weighs 1.5kg.

 

the attached photo is the answer.

 

can u help Write a brief conclusion on the answer that you obtain from the above question. Is it liable and okay to obtain this amount of error? Explain your point of view.

A TOTAL CORRECTION FOR TEMPERATURE
CT : Lx a (Tm - T
CT : 15 39 - 28 X 0.0000 II6 (31 - 20)
CT: 0-19 641m
8. TOTAL CORRECTION DUE TO SAG
|: length of t ape between supports
L- total leng th me as ures
1539-18
no of suppor ts N =
- 15.39
no of bags n: 16-1
* 15
Csag
14n
: 1:5' x 1539. 28
24 K 15' x 10"
Csag : 0.00 6414 m
C. CORRECT LEN GTH OF THE LINE
Cp : (P - Po) x L
AE
(10 -12) x 1539-28
0.035 x 2 x Io
(p : -0.0439 7m
center length of line
L' L Cr Csag I CP
L': 1539. 28 t 0 196 41 t0.006414 - 0-04397
L': 1539. 43 m
Transcribed Image Text:A TOTAL CORRECTION FOR TEMPERATURE CT : Lx a (Tm - T CT : 15 39 - 28 X 0.0000 II6 (31 - 20) CT: 0-19 641m 8. TOTAL CORRECTION DUE TO SAG |: length of t ape between supports L- total leng th me as ures 1539-18 no of suppor ts N = - 15.39 no of bags n: 16-1 * 15 Csag 14n : 1:5' x 1539. 28 24 K 15' x 10" Csag : 0.00 6414 m C. CORRECT LEN GTH OF THE LINE Cp : (P - Po) x L AE (10 -12) x 1539-28 0.035 x 2 x Io (p : -0.0439 7m center length of line L' L Cr Csag I CP L': 1539. 28 t 0 196 41 t0.006414 - 0-04397 L': 1539. 43 m
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