Hi I need help please I need to make a function that converts an infix expression to a post fix expression such as converting a + b * (c-d)Toa b c d - * + Repeat the following for each element in an infix expression:● If an operand is reached, append it to the postfix expression.●●●If an open parentheses is reached, push it to the stack.If a close parenthesis is reached, pop the operators in the stack and append them to thepostfix expression until an open parenthesis is popped.If an operator is reached, pop the operators in the stack that are of higher or equalprecedence than the new operator and append them to the postfix expression. After that,push the new operator to the stack.When the end of the infix expression is reached, pop and append the remainingoperators in the stack and append them to the postfix expression.ch this video and work

Infix expression: An infix expression is one in which the operators (+, -, *, /) are written between…

Answered: Hi I need help please I need to make a…

Hi I need help please I need to make a function that converts an infix expression to a post fix expression such as converting a + b * (c-d) To a b c d - * +

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter18: Stacks And Queues

Section: Chapter Questions

Problem 21SA

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Question

Hi I need help please I need to make a function that converts an infix expression to a post fix expression such as converting a + b * (c-d) To a b c d - * +

Repeat the following for each element in an infix expression:
● If an operand is reached, append it to the postfix expression.
●
●
●
If an open parentheses is reached, push it to the stack.
If a close parenthesis is reached, pop the operators in the stack and append them to the
postfix expression until an open parenthesis is popped.
If an operator is reached, pop the operators in the stack that are of higher or equal
precedence than the new operator and append them to the postfix expression. After that,
push the new operator to the stack.
When the end of the infix expression is reached, pop and append the remaining
operators in the stack and append them to the postfix expression.
ch this video and work

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