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Let 0= cos(-) where 0≤. Find the exact value of 0.

Let 0= cos(-) where 0≤. Find the exact value of 0.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 105E
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Plz do the question like in example i attached plz do it in 30 min plz
Let 0 = cos(-) where 0 << T. Find the exact value of 8.
Transcribed Image Text:Let 0 = cos(-) where 0 << T. Find the exact value of 8.
00 om EXAMPLE 3 Find the exact value of inverse tangent Let = tan-¹(√3) where - << Find the exact value of 0. ▾ SOLUTION 2 /3 By definition, 8=tan(√3) tan0= √3 Since tan@= we know that the adjacent side of the reference triangle is 1 and the opposite side is √3. So we'll use this special triangle to identify the reference angle. 16 From the triangle, we see that √3 is the side opposite from the angle (and 1 is adjacent to this angle). So, the reference angle is =F 3 ***** 3 Since tan -√3 is positive, we know that the terminal side of 9 is in Quadrant I or Quadrant But so we know is in Quadrant I. Since the reference angle = is in Quadrant 1.0 is equivalent to the reference angle. Therefore, 8=
Transcribed Image Text:00 om EXAMPLE 3 Find the exact value of inverse tangent Let = tan-¹(√3) where - << Find the exact value of 0. ▾ SOLUTION 2 /3 By definition, 8=tan(√3) tan0= √3 Since tan@= we know that the adjacent side of the reference triangle is 1 and the opposite side is √3. So we'll use this special triangle to identify the reference angle. 16 From the triangle, we see that √3 is the side opposite from the angle (and 1 is adjacent to this angle). So, the reference angle is =F 3 ***** 3 Since tan -√3 is positive, we know that the terminal side of 9 is in Quadrant I or Quadrant But so we know is in Quadrant I. Since the reference angle = is in Quadrant 1.0 is equivalent to the reference angle. Therefore, 8=
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9:14 ↑ Homework help starts here! Wo Step 2: Finding angle Finding the exact value of 0: (-) /3 -1 By definition, 0 = cos bartleby.com/questio √3 Solution T the reference angle is 0 = 3 Since, cos=- 3 Since, cos= is 2. So, we'lluse the special triangle to identify the reference angle. From the triangle, we see that 1 is the adjacent side from the to the angle So, Still Need Help? FOLLOW UP QUESTION → cos=- --11 is negative, we know that terminal side of is in Quadrant II or III. 2 But 0≤0 ≤7, so, we know that is in Quadrant II. B I ↑ Add Image = 2 we know that the adjacent side of the reference triangle is 1 and the hypotenuse FEEDBACK If you have a question about the solution above, ask a follow-up question! ASK AN EXPERT U x² WAS THIS HELPFUL? X₂ !!! Hi what is the final answer you didn't attach the answer Iml 0 46 | ...| 6 34% O ļ I!! CHAT Ix 2 VX MATH SOLVER and 2 is the hypotenuse. <
Transcribed Image Text:9:14 ↑ Homework help starts here! Wo Step 2: Finding angle Finding the exact value of 0: (-) /3 -1 By definition, 0 = cos bartleby.com/questio √3 Solution T the reference angle is 0 = 3 Since, cos=- 3 Since, cos= is 2. So, we'lluse the special triangle to identify the reference angle. From the triangle, we see that 1 is the adjacent side from the to the angle So, Still Need Help? FOLLOW UP QUESTION → cos=- --11 is negative, we know that terminal side of is in Quadrant II or III. 2 But 0≤0 ≤7, so, we know that is in Quadrant II. B I ↑ Add Image = 2 we know that the adjacent side of the reference triangle is 1 and the hypotenuse FEEDBACK If you have a question about the solution above, ask a follow-up question! ASK AN EXPERT U x² WAS THIS HELPFUL? X₂ !!! Hi what is the final answer you didn't attach the answer Iml 0 46 | ...| 6 34% O ļ I!! CHAT Ix 2 VX MATH SOLVER and 2 is the hypotenuse. <
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