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his question has several parts thát must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to rome back to the skipped part. Tutorial Exercise Find an equation of a sphere if one of its diameters has endpoints (7, 9, 9) and (3, 5, 7). Step 1 The center of the sphere will be the midpoint of the diameter segment. Recall that the midpoint of a segment between the points (u, v, w) and (p, q, s) is given by u + p V + q w + s 2 2 2 Step 2 Therefore, the midpoint of the segment between the given endpoints (7, 9, 9) and (3, 5, 7) is (2놀로, 으늘트, 으늘 ) 7 + 3 9+ 5 9+ 7 2 ' - (5 7 8. 8 Step 3 The radius of the sphere is the distance from this midpoint to either endpoint. Therefore, V (3 - 5)2 + (5 – 7)2 + r = 7 - V 4 + 4 + 28 %3D 36 =

his question has several parts thát must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to rome back to the skipped part. Tutorial Exercise Find an equation of a sphere if one of its diameters has endpoints (7, 9, 9) and (3, 5, 7). Step 1 The center of the sphere will be the midpoint of the diameter segment. Recall that the midpoint of a segment between the points (u, v, w) and (p, q, s) is given by u + p V + q w + s 2 2 2 Step 2 Therefore, the midpoint of the segment between the given endpoints (7, 9, 9) and (3, 5, 7) is (2놀로, 으늘트, 으늘 ) 7 + 3 9+ 5 9+ 7 2 ' - (5 7 8. 8 Step 3 The radius of the sphere is the distance from this midpoint to either endpoint. Therefore, V (3 - 5)2 + (5 – 7)2 + r = 7 - V 4 + 4 + 28 %3D 36 =

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.1: The Rectangular Coordinate System
Problem 44E: By definition, a hyperbola is the locus of points whose positive difference of distances from two...
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his question has several parts thát must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to rome back to the skipped part. Tutorial Exercise Find an equation of a sphere if one of its diameters has endpoints (7, 9, 9) and (3, 5, 7). Step 1 The center of the sphere will be the midpoint of the diameter segment. Recall that the midpoint of a segment between the points (u, v, w) and (p, q, s) is given by u + p V + q w + s 2 2 2 Step 2 Therefore, the midpoint of the segment between the given endpoints (7, 9, 9) and (3, 5, 7) is (2놀로, 으늘트, 으늘 ) 7 + 3 9+ 5 9+ 7 2 ' - (5 7 8. 8 Step 3 The radius of the sphere is the distance from this midpoint to either endpoint. Therefore, V (3 - 5)2 + (5 – 7)2 + r = 7 - V 4 + 4 + 28 %3D 36 =
Transcribed Image Text:his question has several parts thát must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to rome back to the skipped part. Tutorial Exercise Find an equation of a sphere if one of its diameters has endpoints (7, 9, 9) and (3, 5, 7). Step 1 The center of the sphere will be the midpoint of the diameter segment. Recall that the midpoint of a segment between the points (u, v, w) and (p, q, s) is given by u + p V + q w + s 2 2 2 Step 2 Therefore, the midpoint of the segment between the given endpoints (7, 9, 9) and (3, 5, 7) is (2놀로, 으늘트, 으늘 ) 7 + 3 9+ 5 9+ 7 2 ' - (5 7 8. 8 Step 3 The radius of the sphere is the distance from this midpoint to either endpoint. Therefore, V (3 - 5)2 + (5 – 7)2 + r = 7 - V 4 + 4 + 28 %3D 36 =
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