Question

Asked Mar 25, 2019

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H(n) = 0 if n is less than or equal to 0

H(n) = 1 if n=1 or n=2

H(n-1) + H(n-2) - H(n-3) if n>2

prove that H(2n) = H(n-1) +H(n-2) - H(n-3) if n>2

Step 1

The conditions for H(n) is given as,

Step 2

Consider the left hand side of the given equation, which is *H*(2*n*).

Given that, the value of *n* is greater than 2.

Therefore, the value of 2*n* will be alwa...

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