How did you know to use the number 636 for your x in the hit and trial method and not use another number?

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 2EQ: 2. Suppose that in Example 2.27, 400 units of food A, 500 units of B, and 600 units of C are placed...
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How did you know to use the number 636 for your x in the hit and trial method and not use another number?
8:26
←
x+3x+2x-258,4/4,216=0
Step2
b)
The given equation is
x²³²+3x²+2x-958, 474, 216 = 0
using hit and trial method
Put x₁ =
636
(636)³ + 3(636)³ + 2(636)-258,474, 216=0
0 =0
Now x-636
is a factor of eq. D.
40646
X-636x² + 3x² + 2x - 258 4 7 4 2 16 2 2 ² +63 9x + 1980
-£³²=636×1²
634x²+2x
-639x²406404x
(40640) 4othe81 - 258474 2136
+2bost-
406401-258474216
0
O
Now
the oustient is
x²+639x+406 406 = 0
using the quadratic from whe
- b ± √b
ga
where D = b ²2-yac
-639-
1217303 र
-319.5
55 1.657 i
x₂ =
-639 +
1217303
2
-319.5+ 551.6571
- Three roots of the equation is
x₁ = 636, x₂ = -319.5-551.657 i
x3 = -319.5+ 551.6571,
This is the Required Answer.
?
then
LTE
√x
Do
8
Transcribed Image Text:8:26 ← x+3x+2x-258,4/4,216=0 Step2 b) The given equation is x²³²+3x²+2x-958, 474, 216 = 0 using hit and trial method Put x₁ = 636 (636)³ + 3(636)³ + 2(636)-258,474, 216=0 0 =0 Now x-636 is a factor of eq. D. 40646 X-636x² + 3x² + 2x - 258 4 7 4 2 16 2 2 ² +63 9x + 1980 -£³²=636×1² 634x²+2x -639x²406404x (40640) 4othe81 - 258474 2136 +2bost- 406401-258474216 0 O Now the oustient is x²+639x+406 406 = 0 using the quadratic from whe - b ± √b ga where D = b ²2-yac -639- 1217303 र -319.5 55 1.657 i x₂ = -639 + 1217303 2 -319.5+ 551.6571 - Three roots of the equation is x₁ = 636, x₂ = -319.5-551.657 i x3 = -319.5+ 551.6571, This is the Required Answer. ? then LTE √x Do 8
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