Question
Asked Oct 17, 2019
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How do I find the x-coordinate of the point of inflection of f(x)=x(x-8(x)^(1/2))?

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Expert Answer

Step 1

According to the given information the given function whose x coordinates of the point of inflection is to be calculated is:

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f(x)=x\ x-8x2

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Step 2

An inflection point is a point on the graph at which the second derivative changes sign.

So find the second derivative of the graph:

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1 2 -8x2 f(x)=x| x-8x2 f'(x) 2x-12x 1 f"(x) 2-6x

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Step 3

Now, find the value of x where second...

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f"(x) 0 2-6x201-3x =0 -1 x2 = 3 1 3x2 on squaring both sides:

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