How does the angular speed on Moonday (?M) compare to the normal angular speed (?E) of the station?

icon
Related questions
Question

In the year 2220 a new 10-km diameter ring-shaped Space Station has been built to provide artificial gravity by spinning about its axis. On most days, the station spins at ?E = 0.0443 rad/s so that the centripetal acceleration at the edge of the ring matches Earth's surface gravitational acceleration (9.8 m/s2).

However, on the holiday Moonday (the first Monday of the year), the angular speed of the station is changed so that the inhabitants can experience the gravitation acceleration on the surface of the Moon, 1.6 m/s2.

How does the angular speed on Moonday (?M) compare to the normal angular speed (?E) of the station? 


A)ωM = 0.16 ωE
B) ωM = 0.40 ωE
C) ωM = 0.61 ωE
D) ωM = 2.5 ωE
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer