How many bits are required for addressing (i.e. what is the size, in bits, of an address)? 30 bits O 20 bits O 64 bits O 16 bits 32 bits
Q: How many bits would you need to address a 2M x 64 memory if the memory is byte- addressable? Select…
A: We are given memory size as 2M*64 and we are going to find out how many bits would be needed to…
Q: The address of the first word is 0, the second word is 1, the third word is 2, and the last word is…
A: Here word size=64bit = 64/8=8 Bytes.
Q: For a 512k x 32-bit memory system, what is the capacity in bytes? Give the exact number. 2,048,000…
A: INTRODUCTION: Here we need to find the capacity in bytes.
Q: For a 512k x 32 memory system, how many unique address locations are there? Give the exact number. O…
A: Given, Size of memory system = 512k x 32 For a q x r memory system, Number of unique address…
Q: How many address bits are required to access 1024K words of memory?
A: Database Management System(DBMS) is a software for storing and retrieving users data while…
Q: What is the difference between a 7CH bit address and a 7CH byte address? Where in memory does bit…
A: What is the difference between the bit address 7CH and the byte address 7CH? What is the precise…
Q: In order to access 1024K words of memory, how many address bits are required?
A: A database management system - (DBMS) is software that stores and retrieves user data while taking…
Q: Consider a logical address with a page size of 16 KB. How many bits must be used to represent the…
A: The number of bits required to store the page offset in the logical address is 14. Therefore, the…
Q: A computer with a 32-bit address uses a two-level page table. Virtual addresses are split into a…
A: The ask is to calculate the page size and numbr of pages in the address space for a computer with a…
Q: In a page addressing system of 15 bits, where eight bits are used for the page number, what would be…
A: The above question is solved in step 2 :-
Q: Address Content 50 10 51 57 52 21 53 0A 54 52 55 01 56 32 57 CO 58 CO 59 00 Suppose the memory cells…
A: Find the required answer given as below:
Q: Complete the following table given the value %rdx = Oxe800, %rcx = 0x0400 (5 Points) Address Address…
A: %rdx = 0xf800%rcx = 0x0200Expression: 0x80(%rdx)Address Computation: 0xf800 + 0x80Address: 0xf880…
Q: How many addresses do we have if the address is 16 bits long? .a 64K .b M 16 .c 16 .d 1024 1024
A: The correct answer is (a) 64K.
Q: s for addressing mode type, e.g. direct physical address/es e.g. 19000-19001
A: 1)JMP AX Before execution AX=AB8FH A)Addressing Mode: direct B)Physical Address: E66F6,E66F7…
Q: If 20 bits are requires to address 1MB address space, then how many bits are required to address 2…
A: 1 MB= 1000 KB 1 KB= 1000 Bytes 1 Byte =8 Bits
Q: o we need so many addressing modes? Is the ion size influenced by the number of addressing
A: ISA is the portion of the machine which is visible to either the assembly language programmer or a…
Q: A computer has 64 MB (megabytes) of memory. Each word is 4 bytes. How many bits are needed to…
A: As per our answering policy, Only first question is answered.
Q: Consider the virtual memory scheme using paging. The page size is 128 bytes. The entries in the page…
A: In this case, the machine is a 16-bit system with a 4KB page size and 64KB of physical memory.…
Q: What is the minimum number of bits required to address a 32 K memory? 10 bits. 12 bits. 14 bits. 16…
A: Memory Address
Q: What is the maximum address that can be accessed by a 16 bit address bus? a. 32 O b. 2^15 O c. 2^16…
A: The suitable option is (c) 216.
Q: What is the difference between bit address 7CH and byte address 7CH? What is the specific location…
A: Basically, the chip's address space is 16 bits.The corresponding address space is called Byte…
Q: What is the difference between bit address 7CH and byte address7CH? What is the specific location of…
A: Given: What is the difference between bit address 7CH and byte address7CH? What is the specific…
Q: How many address bit a processor need to access 64 TB? Assume byte indexing, word indexing, and…
A: If indexing is byte indexing, then we need to address each byte of the memory Lets say we want to…
Q: What is the physical address of the last memory location in the 8086 Mp (1MByte) memory? What…
A: → In 8086 microprocessor, 16-bit processor has 1Megabyte memory containing a 20-bit address bus.…
Q: For a system that uses 8-KB page size, calculate the page number and offset for the "6070281"…
A: Paging is a memory management strategy that does away with the need for contiguous physical memory…
Q: Compute the address space of the memory with 15 address bits/lines. a. 32,767 O b. 32,768 O c.…
A: In the question address bits are given which represent how much address space it will represent. If…
Q: How convert 16 bit address to 20 bit address explains with the help of example. Which Flag is…
A: I have provided a solution in step2.
Q: Given the page table shown below. What is the physical address (in the binary-number format)…
A: The logical address is <5, 17> The logical address is given in format <page#, offset>
Q: Suppose we have a byte-addressable computer using fully associative o 20-bit main memory addresses…
A: Actually, 1 byte =8 bits. cache memory is a fast access memory.
Q: What is the highest address in MIPS memory architecture referring to a word in hex? The lowest…
A: H . in MIPS 32bit the address can go from 0x0 to 0xffff i.e. 232 - 1 in MIPS 64 bit the address…
Q: For a 512k x 32-bit memory system, what is the capacity in bytes? Give the exact number. Remember…
A: The above question is solved in step 2 :-
Q: How many bits would you need to address a 2M x 64 memory if the memory is byte- addressable? Select…
A: Here we have to find total number of bits required for 2M x 64 memory when memory is byte…
Q: For a system that uses 10-KB page size, calculate the page number and offset for the "200001"…
A: The formula for calculating Page number = (address reference / page size) This is the page number…
Q: Consider a hypothetical memory access time: 1 memory bus clock cycle to send an address
A: Answer: The bandwidth attainable from parallelizing the DRAM initialization time would be 8 words…
Q: Suppose the data segment (DS) holds the base address as 1100h and the data you need is present in…
A: Suppose data segment hold base address 1100h and present in physical memory location 0021h calculate…
Q: The memory units that follow are specified by the number of words times the number of bits per word.…
A: Explanation: An address line indicates the physical storage directly to access and store data. A…
Q: A main memory in a computer uses pages of 1024 bytes and has a page table of 64 entries. What is the…
A: Task :- choose the correct option for given question.
Q: How many bit address is required to address: 1KB, 2KB, 4KB, 1MB, 1GB and 4GB of RAM? How many bit…
A: Introduction: Here we are required to mention how many bit address is required to address: 1KB, 2KB,…
Q: Suppose a memory chip consisted of 256, 16-bit words. How many address lines would be needed? а. 8 O…
A: Given data : 256 words , 16 bit each size - We have to find the number of address lines. - we know…
Q: A computer that generate 16- bit addresses is capable of addressing up to memory locations. O 64 kB…
A: Computer Memory: The data storage technologies used in a computer system are collectively known as…
Q: A ROM having a capacity of 16 K and 8 output lines is given. How many address lines are there? (Note…
A: Given ROM capacity 16K x 8 ROM capacity as 2^m x n Where m is no of address lines n is no of data…
Q: An address's first 24 bits reflect what?|
A: The first 24 bits of an address reveal a great deal about what it represents. The first eight bits…
Q: How many address bits are needed to reach 1024K words of memory?
A: Number word present in a memory = 1024K word…
Q: Q2/(A) Write an ALP to clear bits 0 to 4, set bits 5 to 9 and complement bits 10 to 15 in a memory…
A: ALP programming: ============================================================================= MOV…
Q: For a system that uses 4-KB page size, calculate the page number and offset for the "96312" address…
A: Given page size = 4KB = 4000 Bytes Address reference = 96312
Q: For a 512k x 32 memory system, what is the data width at each address location? 19 32 512k 16M
A: Given, Size of memory system = 512k x 32 For a m x n memory system, Size of address = log 2 m Size…
Q: 1. Suppose the Vole memory cells from addresses 0x00 to 0x05 contain the bit patterns given in the…
A: We must demonstrate the execution of the above-mentioned assembly program in which the vole cell…
Q: How many address bits are required for a 2048-bit memory organized as a 256 * 8 memory?
A: GIVEN: How many address bits are required for a 2048-bit memory organized as a 256 * 8 memory?…
Q: Suppose a memory chip consisted of 256, 16-bit words. How many address lines would be needed? 5 O…
A: since we have 256M (2^8=256) we will need 8 lines.
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Will upvote! Find the memory address of the next instruction executed by the microprocessor, when operated in the real mode, for the following CS:IP and 80286 register combinations: a. DS=2F2E & DX=9D64 b. CS=9F7A & IP=AB27 c. ES=DE21 & DI=D75F d. SS=FF5C & BP=92B8 e. DS=DC67 & CX=2FE8The register content for an Intel 8086 microprocessor is as follows:CS = 1000H, DS = 2000H, SS = 5000H, SI = 2000H, DI = 4000HBX = 6783H, BP = 7000H, AX = 29FFH, CX = 8793H, DX = A297HCalculate the physical address of the memory where the operand is stored and the contents of the memory locations in each of the addresses shown below: a) MOV [SI], ALb) MOV [DI+6H], BXc) MOV [SI+BX–11], AXd) MOV [DI][BX]+28H, CXe) MOV [BP][SI]+17, DX
- A two-word instruction is stored in memory at an address designated by the symbol A. The address field of the instruction (stored at A + 1) is designated by the symbol Y. The operand used during the execution of the instruction is stored at an address symbolized by EA. An index register contains the value X. With the help of diagram, state how EA is calculated from the other addresses if the addressing mode of the instruction is (1)- direct (2)- indirect (3)- indexed (4)-Relative (5)- Register indirect1. T/F - if (B)=006000 (PC)=003600 (X)=000090, for the machine instruction 0x032026, the target address is 003000.2. T/F – PC register stores the return address for subroutine jump.3. T/F – S register contains a variety of information such as condition code.4. T/F – INPUT WORD 1034 – This means Operating system should reserve 1034 bytes in memory5. T/F - In a two pass assembler, adding literals to literal table and address resolution of local symbol are done using first pass and second pass respectively.If R0 = 0x20008000, after STMDA r0!, {r3, r9, r7, r1, r2} instruction is executed, register r7 will be stored in memory starting from which memory base address. A. R0 = 0x20007ff0 B. R0=0x20007fec C. R0 = 0x20007fff D. R0= 0x20007ff4 E. R0 = 0x20007ffef
- A SUB instruction stores a value 8467h at offset value BD3Fh. If the computed address is 5B68Eh, what will be the ending address? Assume real mode operation. O a. 5F94E O b.5F94E0 O c. 4F94F O d. 4F94F0You have a CPU which contains two processor cores, connected via a bus. Each core has its own 8 row, direct-mapped L1 cache and the two caches are coherent via snoopy cache coherent over the bus, with a write-invalidate mechanism. The block size in the cache is 8 bytes (two words). Core A: Load byte address 63 Core A: Load byte address 57 Core B: Store byte address 63 Core A: Store byte address 63 Core B: Load byte address 102 Core A: Load byte address 121 Core A: Load byte address 57 For each access from the list above, please indicate whether the access would be a hit, a compulsory miss, a conflict miss, a capacity miss, or a coherence miss. Before the sequence begins, both caches are empty. First access (Core A address 63): Second access (Core A address 57): Third access (Core B address 63): Fourth access (Core A address 63): Fifth access (Core B address 102): Sixth access (Core A address 121): Seventh access (Core A address 57):Single instruction computer (SIC) has only one instruction that for all operations our MIPS does. The instruction has the following format. sbn a, b, c # Mems[a]=Mem[a]- Mem[b]; if (Mem[a]<0) go to PC+c For example, here is the program to copy a number from location a to location b: Start: sbn temp, temp, 1 sbn temp, a, 1 sbn b, b, 1 sbn b, temp, 1 So build SIC program to add a and b, leaving the result in a and leaving b unmodified.
- Compute the physical address for the specified operand in each of the following instructions from previousproblem. The register contents and variables are as follows : (CS) = 0A0016, (DS) = 0B0016, (SI) =010016, (DI) = 020016 and (BX) = 030016.a) Destination operand of the instruction in (c)b) Source operand of the instruction in (d)c) Destination operand of the instruction in (e)d) Destination operand of the instruction in (f)e) Destination operand of the instruction in (g)Consider the following store instruction: SW R1, 0x000F(R0). Assume that the registers R0 and R1 are initialized with 0x00000001 and 0x53A78BC Frespectively. A section of the MIPS byte addressable data memory is shown. Give the memory word of the following memory locations after the SW operation: (a). 0x00000015. (b). 0x00000014. (c). 0x00000013. (d) 0x00000012.(e). 0x00000011. (f). 0x00000010.Assume that the state of the 8088’s registers and memory just prior to the executionof each instruction in problem 15 is as follows: * in photos*What result is produced in the destination operand by executing instructions (a)through (k)? *only h through k* (h) MUL DX(i) IMUL BYTE PTR [BX+SI](j) DIV BYTE PTR [SI]+0030H(k) IDIV BYTE PTR [BX][SI]+0030H