how many functions a) map {1,2,3.4.5.6} to {up,down,left,right} b) how many functions in part a are subjective? c) how many have f- inverse(up) =2
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how many functions
a) map {1,2,3.4.5.6} to {up,down,left,right}
b) how many functions in part a are subjective?
c) how many have f- inverse(up) =2
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- Let A = {1, 2,3} and B = {a, b, c, d} What is the function from a to b?Explain work a function works with relevant example s1. Question : Simplify the following functions using Boolean algebra rules: F1 = a.b+c’+c(a’+b’) F2 = (x.y’+z)(x+y’)z 2. Question : Convert the following function to POS standard form F3 = (? + ?) (?̅+ ? + ?) • Convert the following function to SOP standard form F4 = (? + ?) (?̅+ ? + ?) 3. Question : • Use K-maps to minimize the following functions F5 = a’b’d+a’bc’d+a’bcd F6 = ∑(0,2,5, 9,10 11,12,13)
- Define Functions fill and fill_n.Redo problem 2 where you have to define and use the following functions: (a) isTriangle - takes 3 sides of a triangle and returns true if they form a triangle, false otherwise. (b) isIsosceles - takes 3 sides of a triangle and returns true if they form an isosceles triangle, false otherwise. (c) isEquilateral - takes 3 sides of a triangle and returns true if they form anequilateral triangle, false otherwise. (d) isRight - takes 3 sides of a triangle and returns true if they form a right triangle, false otherwise. (e) your program should run continuous until the user wants to quit this is my problem 2: #include <iostream> #include <cmath> using namespace std; // Constant Declarations const double E = .0001; int main() { double side1, side2, side3; bool isTriangle, isRight, isEquilateral, isIsosceles; cout << "Enter the lengths of the 3 sides of a triangle -- "; cin >> side1 >> side2 >> side3; isTriangle = side1 + side2 > side3 &&side1 +…Determine whether each of these functions is a bijection from ℝ to ℝ. If it is, write the inverse function. ?(?) = 3|?| − 4
- Using a relevant example, explain how a function works.(a) Write the C++ function, operator+(const Matrix& b) const, which returns the matrix *this + b.1.1 Devise formulas for the functions that calculate my first i and my last i in the global sum example. Remember that each core should be assigned roughly the same number of elements of computations in the loop. Hint: First consider the case when n is evenly divisible by p.
- State whether each of the following functions is injective, surjective, bijective, or none ofthese categories: (N is the set of natural numbers, and Σ∗is the set of all strings over Σ.)(a) f : N → N , f(n) = n div 3(b) g : N → N , g(n) = n2 + 2n + 1 (c) h : Σ∗ → Σ∗, where Σ = {a, b}, and h(w) = a|w| (d) h : Σ∗ → Σ∗, where Σ = {a, b}, and h(w) = wRState whether each of the following functions is injective, surjective, bijective, or none ofthese categories: (N is the set of natural numbers, and Σ∗is the set of all strings over Σ.)(a) f : N → N , f(n) = n div 3(b) g : N → N , g(n) = n2 + 2n + 1(c) h : Σ∗ → Σ∗, where Σ = {a, b}, and h(w) = a|w|. (d) h : Σ∗ → Σ∗, where Σ = {a, b}, and h(w) = wR.TROUBLESHOOTING: Fix the errors in the code below and run the script with your modified code function [x,numIter,omega] = gaussSeidel(func,x,maxIter,epsilon) % Solves Ax = b by Gauss-Seidel method with relaxation. % USAGE: [x,numIter,omega] = gaussSeidel(func,x,maxIter,epsilon) % INPUT: % func = handle of function that returns improved x using % x = starting solution vector % maxIter = allowable number of iterations (default is 500) % epsilon = error tolerance (default is 1.0e-9) % OUTPUT: % x = solution vector % numIter = number of iterations carried out % omega = computed relaxation factor if nargin < 4; epsilon = 1.0e-9; end if nargin < 3; maxIter = 500; end k = 10; p = 1; omega = 1; for numIter = 1:maxIter xOld = x; x = feval(func,x,omega); dx = sqrt(dot(x - xOld,x - xOld)); if dx < epsilon; return; end if numIter == k; dx1 = dx; end if numIter == k + p omega = 2/(1 + sqrt(1 - (dx/dx1)ˆ(1/p))); end end error(’Too many iterations’)