How many memory addresses can a microprocessor 68000 Motorola system access? It must be proven and the memory location's final address must be justified. Use this address to draw a memory map of the object, then.
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How many memory addresses can a microprocessor 68000 Motorola system access? It must be proven and the memory location's final address must be justified. Use this address to draw a memory map of the object, then.
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- For a microprocessor 68000 Motorola system, how many memory addresses which can be accessed by it? Prove it and justify the last address of the memory location. Then, sketch the memory map of it by using the address calculated.What is the difference between segmented memory address translation and direct translation?Can a specific physical address have more than two logical addresses? Give your opinion with examples. Suppose you have a microprocessor which has 16MB of total physical memory. In this case what would be the size of the address bus?
- Why is segmented memory address translation preferable to simply translating everything at once?Suppose the RAM for a certain computer has 4M words, where each word is 16 bits long. What is the capacity of this memory expressed in bytes? If this RAM is byte addressable, how many bits must an address contain? If this RAM is word addressable, how many bits must an address contain?For a microprocessor to operate, let assume that it requires 2MB of RAM and 7MB of ROM. What is the minimum number of address lines the microprocessor must support? Draw a memory map of the system, assuming that the addresses for the RAM are below the addresses for the ROM.
- Explain with a diagram the process of mapping a logical address to a physical address in the main memoryWhy is it preferable to use segmented memory address translation instead of just translating everything at once?Consider a memory implemented for 8086 microprocessor Draw the memory block diagram. Determine the values for A0 , /BHE ,address lines(A1..A19) and data lines(D0.. D15) in order to access: A byte at odd address [01FF3H] A byte at even address [01FFCH] A word at even address [01FFEH] A word at odd address [01ABFH]
- If we already have RAM (random access memory), which may be used as volatile memory and has a very similar architecture to cache memory, then cache memory could appear unneeded. Can a computer function with only one kind of memory?Why is it preferable to use fragmented memory address translation rather than just translating the addresses in question?Memory address translation is useful only if the total size of virtual memory (summed over all processes) needs to be larger than physical memory. True or False. Justify your answer.