How many terms of the series do we need to add in order to find the sum to the indicated accuracy? (-1)"–1 error < 0.008. n2 n=1 10 nter the smallest possible integer.

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Q: The nth term of the series .. IS: Select one: a. n an %3D n+1 O . 1 an 0,-(-) n+1 OC. an = (1-1/n)

A: Proceed as shown below...

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A: Introduction: A Taylor polynomial's Lagrange error bound represents the worst-case scenario for the…

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Q: Find all the values of x such that the given series would converge. (x – 8)" 8 n=1 Answer: Note:…

A: Explanation of answer is as follows:

Q: Express the given power series as a series with generic term x". 00 Σ n+3 n+3 n=8 Σ

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Q: Approximate the value of the series to within an error of at most 10 -3 (-1)"+1 (n + 7)(n + 8)…

A: GIVEN∑n→1∞(-1)n+1(n+7)(n+8) we need to find the smallest value of N that approximates S to within an…

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A: We have to test the convergent

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Q: Determine how many terms of the following convergent series must be summed to be sure that the…

A: Since we know that, Error=Rn≤an+1 Where an+1 is a magnitude of (n+1)th term in the sequence.

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Q: Find all the values of x such that the given series would converge. * (x – 10)" 10" n=1 The series…

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Q: Find all the values of x such that the given series would converge. 00 x" (5)"(\n + 7) n=1 The…

A: ∑n=1∞ xn5nn+7

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Q: 33. Find the Maclaurin series for e-, and use it to approx- 1 to within 0.001 of its value. How many…

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A: Given: The series  Here the kth term is

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Q: Find all the values of x such that the given series would converge. * (9x)" 00 Σ n=1 The series is…

A: Given series,   ∑n=1∞an=∑n=1∞9xnn9

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A: By Alternating series estimation series test : s=∑n=1∞(-1)nbn        1)  bn+1≤bn2)  limn→∞ bn=0Then…

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Q: Find all the values of x such that the given series would converge. (9x)" 00 n8 n=1 The series is…

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Q: How many terms of the Maclaurin series of f(x) = ln (1+x) are needed to compute In(1.5) to within an…

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Q: a, where a, = (-1)"+". n2 + 9 Consider the series n=1 Using the alternating series error estimation…

A: Given :-  Consider the series ∑n=1∞ an  where an =  -1n+5 nn2 + 9

Q: How do I find the upper bound of the series, where p is less than one?

A: To show that an upper bound does not exist for the given series (p&lt;1) .