How many times will the following code will print "Final Test"? int i = 3; while (i > 0) { i--; System.out.println("Final Test"); } four times one time three times none
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(JAVA program language) I want last answer only, Idont need the explain.
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- How many times will the following code will print "Final Test"? three times none one time four timesBelow is a nested loop containing an assignment statement. How many times will the assignment statement (z = z + 1) execute up to big theta? int z; for (int x = 1; x <= n; x++) { for (int y = 1; y <= floor(i / 3); y++) { z = z + 1; } }Use JAVA CARD GRAPHICS to create a card game in which the dealer shuffles the deck and deals 13 cards to the player. The player sorts her hand and says whether it includes the King of Hearts. Repeat 4 times so all the cards are dealt eventually. Internally, the player should return true or false without writing to the console. In response, the dealer should write on the console, "You won!" or "You loose again." Also create a unit test for the win and loose cases.
- What will the following code display?try:x = float('abc123')print(x)except IOError:print('This code caused an IOError.')except ZeroDivisionError:print('This code caused a ZeroDivisionError.')except:print('An error happened.')print('The end.')Write an application that allows a user to enter any number of student quiz scores, as integers, until the user enters 99. If the score entered is less than 0 or more than 10, display Score must be between 10 and 0 and do not use the score. After all the scores have been entered, display the number of valid scores entered, the highest score, the lowest score, and the arithmetic average.What value will z have if we execute the following assignment statement? Please elaborate on your answer. int z = 50 / 10.00;
- I don't know how to do this. Thanks in advance. Modify the CountByFives application from Chapter 6 Programming Exercise 1A so that the user enters the value to count by. Start each new line after 10 values have been displayed. public class CountByAnything { // Modify the code below public static void main (String args[]) { final int START = 5; final int STOP = 500; final int NUMBER_PER_LINE = 50; for(int i = START; i <= STOP; i += START) { System.out.print(i + " "); if(i % NUMBER_PER_LINE == 0) System.out.println(); } } }The following code results in an error message. What will the error message be andhow can it be fixed? def TryParseInt(p1, p2):return p1 + p2#Calling Codep3 = TryParseInt(10)Please find the running time of the program below. See attached photo for example. int exam_1(int n) { int i, j, k, sum = 0; for(i=3; i<=n * 3; i+=3) { for(j=1; j<=n; j++) { for(k=2; k<=j; k* =2) { sum = sum + k * i; if(sum > j) { sum = sum + 1; } } } }}
- I cannot get the return total part to work, this is in python by the way. WEIGHT_LIMIT = 100COUNT_LIMIT = 4wizard_inventory=[] def display_title(): print("The Wizard Inventory program") print() def display_menu(): print("COMMAND MENU") print("show - Show all items") print("grab - Grab an item") print("edit - Edit an item") print("drop - Drop an item") print("exit - Exit program") print() def show(inventory): print("Show inventory")for i in inventory: print(i[0],i[1],"(",i[2],")lbs") total = calculate_weight(inventory)print("Total Weights is : ",total,"lbs")print(" Weight limits of 100 lbs") def calculate_weight(inventory): total =0for i in inventory: print(i[2]) total = total + i[2]return total def grab_item(inventory): list = [] total = 0if(len(inventory)<4): list.extend(get_new_item()) total = calculate_weight(inventory) total = total + list[2] print(total)if(total < 100): inventory.append(list)else:…/*** Returns true if the user has exceeded maximum number of turns (if tries >= MAXTURNS). * If loss returns true, method will print am essage to the user indicating that the user has lost, and what the correct word was.* @param tries* @param word* @param MAXTURNS* @return true if the user has exceeded number of turns, false otherwise*/public static boolean loss(int tries, String word, int MAXTURNS) { }}"""This program will look for the next perfect square.Check the argument to see if it is a perfect square itself, if it is not then return -1 otherwiselook for the next perfect square.for instance if you pass 121 then the script should return the next perfect square which is 144.""" def find_next_square(sq): root = sq ** 0.5 if root.is_integer(): return (root + 1)**2 return -1 def find_next_squa2(sq): """ Alternatie method, works by evaluating anything non-zero as True (0.0001 --> True) """ root = s**0.5.
