Show that the function is increasing on the given open interval. (Enter your answers as a comma-separated list if necessary.)y = x5; increasing on (−∞, ∞)We have y'(x) = . y'(x) = 0 when x = . Therefore, the critical numbers are x = . Finally, since y'(−1) = and y'(1) = , we have that y is increasing on (−∞, ∞). Show that the function is increasing on the given open interval. (Enter your answers as a comma-separated list if necessary.)y = x5; increasing on (-00, 00)We have y'(x) =and y'(1) =. y'(x) = 0 when x =we have that y is increasing on (-00, 00).. Therefore, the critical numbers are x =. Finally, since y'(-1) =

Answered: Image /qna-images/answer/dbaa3877-0c2f-44a5-af64-2ec10649cf36.jpg

how that the function is increasing on the given open interval. (Enter your answers as a comma-separated list if necessary.) y = x5; increasing on (-00,00) We have y'(x) = and y'(1) = . y'(x) = 0 when x = , we have that y is increasing on (-00, 00). Therefore, the critical numbers are x = . Finally, since y'(-1) =

how that the function is increasing on the given open interval. (Enter your answers as a comma-separated list if necessary.) y = x5; increasing on (-00,00) We have y'(x) = and y'(1) = . y'(x) = 0 when x = , we have that y is increasing on (-00, 00). Therefore, the critical numbers are x = . Finally, since y'(-1) =

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

Show that the function is increasing on the given open interval. (Enter your answers as a comma-separated list if necessary.)

y = x⁵;

increasing on

(−∞, ∞)

We have

y'(x) =

y'(x) = 0

when

x =

Therefore, the critical numbers are

x =

Finally, since

y'(−1) =

and

y'(1) =

we have that y is increasing on

(−∞, ∞).

Show that the function is increasing on the given open interval. (Enter your answers as a comma-separated list if necessary.)
y = x5; increasing on (-00, 00)
We have y'(x) =
and y'(1) =
. y'(x) = 0 when x =
we have that y is increasing on (-00, 00).
. Therefore, the critical numbers are x =
. Finally, since y'(-1) =

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