h(t) = Ve - 4e°

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 61E
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How would I go about to differentiate the function in the image?

 

Would ^4 Square root (t) be written as t^1/4? Then would the differential be 1 x 1/4 t ^ 1/4 - 4/4 = 1/4t^-3/4 ?

 

Does 4e^t remain the same? if so why?

h(t) = VE - 4et
Transcribed Image Text:h(t) = VE - 4et
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