h(x) = [(x − 3)√6x − x² + 9 sin¯¹ (x-³)] g(t)e-2t (1+e-2t)-1/2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Instructions: what is the derivative of the given functions? 

 

h(x) = [(x − 3)√6x − x² + 9 sin−¹(x-³)]
g(t) = e-2t (1+e-²t)-1/2
Transcribed Image Text:h(x) = [(x − 3)√6x − x² + 9 sin−¹(x-³)] g(t) = e-2t (1+e-²t)-1/2
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