Substituting these expressions into the system shown earlier yields the following system. (cos 5t)v₁' + (sin 5t)v₂' = 0 " (-5 sin 5t)v₁ + (5 cos 5t)v₂ = 4 sec 5t Solve this system for v₁ '(t) and v₂'(t). V₁ '(t) = V₂' (t) = 5 4 5 tan 5t

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