RFigure 2: The Bayesian network required for Q3 (b).(b) Uncertainty.Consider the following simple description of faults in the brakes of a bus. Twoproblems may cause a brake repair to be necessary. These are a leak in the brakefluid cable, and worn brake pads. If either of these happens, one of two thingsmay alert the driver to the problem: either noticeably reduced braking powerin the bus, or an indicator light of a brake fault on the dashboard. If the driverobserves either of these problems, they should take the bus to a garage for repair.Figure 2 shows the Bayesian network for modelling repairs in a bus. Nodes rep-resent the following: L for a leak in the brake cable; P for a worn brake pad; Ffor à fault in the brakes; R for reduced braking power; I for an indicator light of afault on the dashboard; and G for the bus is taken to a garage for a brake repair.(i) Give an informal description of why the arrows in the diagram are neces-sary, and why the arrows which are not present may be omitted correctly.(ii) Suppose we are given the following conditional probability values forthe Bayesian Network: P(L)P(F|notL, P) =0.99, P(F|L, not P) = 0.99, P(F|notL, notP) = 0.1.From these values and the diagram, calculate the value of P(F) to threedecimal places0.1, P(P)0.2, P(F|L, P) = 0.999,%3D

rеpair. (i) Give an informal description of why the arrows in the diagram are neces- sary, and why the arrows which are not present may be omitted correctly. (ii) Suppose we are given the following conditional probability values for the Bayesian Network: P(L) P(F\notL, P) = 0.99, P(F|L, not P) = 0.99, P(F|not L, notP) = 0.1. From these values and the diagram, calculate the value of P(F) to three decimal places 0.1, P(P) 0.2, P(F|L, P) 0.999, %3D

rеpair. (i) Give an informal description of why the arrows in the diagram are neces- sary, and why the arrows which are not present may be omitted correctly. (ii) Suppose we are given the following conditional probability values for the Bayesian Network: P(L) P(F\notL, P) = 0.99, P(F|L, not P) = 0.99, P(F|not L, notP) = 0.1. From these values and the diagram, calculate the value of P(F) to three decimal places 0.1, P(P) 0.2, P(F|L, P) 0.999, %3D

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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