(i) L-1 (i) L- s-5)

Q: 1 -1/2R2 = R2 1 1 1 1/32R3 = R3 1 1 1 1 1 1 -1/5R4 = R4 1 1 1 1 1 1 1

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Q: s+2s ds s2+1

A: I have stated the used formulas in the solution.

Q: Evaluate the function at the indicated values.

A: Given: The function kx=2x3-3x2, To find: The value of k0, k3, k-3, k12, ka2, k-x, kx3

Q: 2 -1 -5 0 2 1 0 O - 2 3 1 D = 2 -2 -4 2 -7 0 -1 2 4 -6 -5 -9 -5 0 1 2 2. 3. 1. 3. 2.

A: A=2-1502210-23135102-20-42-70-12234-6-5-90-50126

Q: Xi: 216,31! Y: 3,9,612 の-) さx:-3)(Y: -5) のT(X:-s)(Y;-5) Xi

A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

Q: 5s-2 d. s²(s+2)(s-1)

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Q: (-1| +J-100) + (as- J-64)

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Q: e3t -1-3t { 9 O 3/(s^2(s-3)) O 1/(s^2(s+3)) O -3/(s^2(s+3)) 1/(s^2(s-3))

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Q: S² z²√√(-z² + 1)5 dz

A: To find the value of the given integral.

Q: 26 E(- 1)"2n - %3D n=0

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Q: 2 + 3s (s + 2)³ = (-21² + 3t) e-2i

A: Follow the procedure given below.

Q: Evaluate the function at the indicated values.

A: kx=-x2-2x+3

Q: 2 -1 -5 0 2 2 1 0 -2 3 D = 5 1 0 2 -2 0 -4 2 -7 0 -1 2 2 4 -6 -5 -9 -5 0 1 2 6 3. 1. 3.

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Q: s+3 L[e-3t cosh( 3t)] = %3D (s-3)²–9 True False

A: Disclaimer: Since you have asked multiple questions, we will solve the first question for you. If…

Q: 2(k, e) = (-2)* f(k – () + 2/9 + /3l. %3D |

A: The given equation is,                       z(k,l)+2z(k-1,l-1)=l ....................(i) let k-l=m

Q: 18. y = -x + 2, y = x- 3, x= -1, x = 1

A: *As per our guideline we are allowed to answer only 1 question at a time.Kindly please re-post other…

Q: 2 2n² 1-n²¹ 1+n³ 1+n³ 202-1-n 3 1+n³ Simplify Show your work. 2

A: Simplifying the given expression

Q: Activity 4 s+2 1.1 s(s-3) 2.1. s(s-2)3

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Q: 33. z = -V3 + i

A: Given: The complex number z=-3+i, To find: Polar form of given complex number.

Q: (3) 2.3-= 3" – 1 i=1 k+1 Hint: 2-3-1 = 2-3i-1+2-3'k+1)-1 = 3* –1+2-3* = 3-3* –1 = 3*+1_1 i=1 i=1

A: ∑i=1n2.3i-1=3n-1for  n=1∑i=1n2.3i-1=2.30=2=31-1,    truefor n=2∑i=1n2.3i-1=2.30+2.31=2+6=8=32-1,…

Q: 4-¹ {√ 5. L- -48 se (3s + 2)(s - 2)

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Q: السؤال 25 J -3 (x) =J3(x) صواب خطأ

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Q: L{2et – 4e4 } O 2(s-6) 52-6s+8 O2 (6-s) 52-6s+8 s-6 82 6s+8 (s 6) 2 6s+8

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Q: cosh(z3)

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Q: 를 + 2 I→-5 5-+x

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Q: 4s+4 s2(s-2)

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Q: 3) passing (-1,-2) and mrmal to y-2x +4 = 0

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Q: h(x) = e−3x;    h(1/4), h(2.5), h(−1), h(−?) h(1/4)= h(2.5)= h(-1)=

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Q: 28-3 s+s-2 3. 2¹{F(s)} for F(s)=-

A: 3.

Q: x 2 s 2) = 1

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Q: P(A)-0.49 PCB) = 0.62 %3D

A: Since A and B are mutually exclusive events, PA∩B=0 1. Consider the property of complementary…

Q: 3) O-x)シーシ=0

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Q: x = 1 - 41, y = 3 +1, 2 =8-61 x= 2+ 3s, y = 2s, z = -I- 35.

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Q: ОА. (х+82 + (у - 9)2 3 9 О В. (х+9)2 + (у -8)2 %3 3 OC. (x-9)2 + (y + 8)2 = 3 O D. (x-8)2 + (y + 9)²…

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Q: (a) L-1 .(s+2)²(s-2). 1 (b) L- (s+1)(s²+1).

A: Given The given inverse Laplace transforms are a L-1ss+22s-2 b L-11s+1s2+1 Apply formula…

Q: (2s+5)e-2s i. s²+5s+6 se-35+2 ii. s² +2s+2

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Q: 2- E(-1)"

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Q: (8 – 4)e-3s s2 – 4s + 5 Determine L-1

A: The inverse laplace transform rule. If L-1Fs=ft then 1. L-1e-asFs=Ht-aft-a, Here, H(t) is Heaviside…

Q: an + 7 2. a %3D

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Q: (i) ae2* + 2xe²* = 8e2« (ii) e2 – 6e" – 16 = 0 (iii) In z+ In(r – 3) = In(5x – 7)

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Q: 4n+3 IIi II i = k=1

A: We now that : ∏ implies the product of numbers. And ∏k=1nk=1.2..............n Therefore according to…

Q: 25 an - 1 %3D 3 (Simplify your ans a5 II

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Q: determine L−1[F].

A: Consider the following function: Fs=s+2s+22+9=s+2s+22+32 Consider the following formulae:…

Q: -6 > 2 x+3 Show your work: O (-6] O (-6, 00) O -6, 3) O (-0, -6) U (-3, 0)

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Q: 4-1 { 27. 9-1 2s - 4 (s² + s)(s² + 1))

A: Solution :

Q: P(-0.34<Z < 2.46) = (Using table E) %3D

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Q: 6. Between z= -1.53 and z=0

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Q: (ke) 3 (1-In 2-) 1. For Sk*e3* dx = +C.f u= 3x, then k=? 2.

A: