I need help to solve this  Explain the concept of wave propagation in a good conducting medium and hence derive the following parameters: i. Attenuation and phase constant ii. Skin depth iii. Wave velocity and iv. Wave Impedance

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter4: Transmission Line Parameters
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I need help to solve this 

Explain the concept of wave propagation in a good conducting medium and hence derive the following parameters:
i. Attenuation and phase constant
ii. Skin depth
iii. Wave velocity and iv. Wave Impedance

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We know that
ß = W
14
ME
2
For good conductor, I >> 1 => />
عل
ß=
2
14
{1+ (1/2) = + 1}]}
WE
how we get this equution?
But it I also
WE
o
WE.
also ~ WE
= W| ME
2
X
Ō
WE
عله
шмо
2
7 B = 21Tf Mo
2
3 =
TTF MO rad/m
Transcribed Image Text:We know that ß = W 14 ME 2 For good conductor, I >> 1 => /> عل ß= 2 14 {1+ (1/2) = + 1}]} WE how we get this equution? But it I also WE o WE. also ~ WE = W| ME 2 X Ō WE عله шмо 2 7 B = 21Tf Mo 2 3 = TTF MO rad/m
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Follow-up Question

From where get this formula ?! 

Solution b BY BARTLEBY EXPERT
Step 1
We know that
x =
3
=>
МЕ
x = W
11+/012
(WE
For good conductor, WE
o >>I
МЕ
11/²2 { ₁ + √ √ 2 - 1 }
WE
=> x = w M8 x WE
-1}
from
where
derive
this
equation ??
2
.. (1 + (5 (1) ²
ωε
≈1+5
WE
Transcribed Image Text:Solution b BY BARTLEBY EXPERT Step 1 We know that x = 3 => МЕ x = W 11+/012 (WE For good conductor, WE o >>I МЕ 11/²2 { ₁ + √ √ 2 - 1 } WE => x = w M8 x WE -1} from where derive this equation ?? 2 .. (1 + (5 (1) ² ωε ≈1+5 WE
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Follow-up Question

I need mathmatics solving for derive Attenuation, phase constant
 Skin depth,Wave velocity and  Wave Impedance .

 like this picture I proveded but in clearly explaintion to understand the concept

W
WE
Attenuation
WE
α =
x =
ß =
(6) >>
B = w
∞ -
ß
w=2πif
>>
w
>>1
w / Ne
1
Ce
لا
√₁
№² 2 √1-4(62²22)-13
Jc >> Jd
NE
2
V
Jose
どでの
2
√TTfNG
13
Neps Im
Nep /n
√HE WHE
LE
हर
fro
WON = √√TifNG
2
2
NE 1/1/12 +13
2
+
Nepes /m
13
rad/m
Transcribed Image Text:W WE Attenuation WE α = x = ß = (6) >> B = w ∞ - ß w=2πif >> w >>1 w / Ne 1 Ce لا √₁ №² 2 √1-4(62²22)-13 Jc >> Jd NE 2 V Jose どでの 2 √TTfNG 13 Neps Im Nep /n √HE WHE LE हर fro WON = √√TifNG 2 2 NE 1/1/12 +13 2 + Nepes /m 13 rad/m
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