I need help with number 5. Please explain. Number CountedPurple & smoothPurple & shrunkenYellow & smoothYellow & shrunken19,20,22,20,20 = 1016,7,5,5,7 = 306,5,4,5,5 = 251,1,2,0,0 = 4TOTAL 1603. Did you obtain a 9:3:3:1 ratio? To determine if the deviations from your observed data are due to chance aloneor if the data is significantly different, you need to use a chi square test. The table below will help you make thecalculations.Expected NumberObserved Number [Observed - Expected ]²+ еxpectedPurple & smoothPurple & shrunkenTotal x 9/16 = 90101(101-90)^2/90 = 1.34Total x 3/16 = 3030(30-30)^2/30 = 0Yellow & smoothTotal x 3/16 = 3025(25-30)^2/30 = 0.83Yellow & shrunkenTotal x 1/16 = 104|(4-10)^2/10 = 3.65.77CHI SQUARE VALUE ========(add the numbers from the rows above)4. Now determine if your chi square value is a good fit with your data. Your degrees of freedom (df) is the numberof possible phenotypes minus 1. In your case, 4 - 1 = 3. Find the number in that row that is closest to your chisquare value. Circle that number.5. Explain what it means to have a "good fit" or a "poor fit". Does you chi square analysis of real corn data supportthe hypothesis that the parental generation was PpSs x PpSs?Chi Square Problem SetGood Fit Between Ear & DataPoor Fit1. Problem: A large ear of corn has a total of433 grains, including 271 Purple & starchy, 73Purple & sweet, 63 Yellow & starchy, and 26Yellow & sweet.df.90.70.60.5020.10.05.011.02.15.31461.642.713.856.64Your Tentative Hypothesis: This ear ofcorn was produced by a dihybrid cross(PpSs x PpSs) involving two pairs ofheterozygous genes resulting in atheoretical (expected) ratio of 9:3:3:1.2.21.711.051.393.224.605.999.21.581.421.852.374.646.257.8211.3441.062.202.783.365.997.789.4913.28Objective: Test your hypothesis using chisquare and probability values.

Question

I need help with number 5. Please explain. Number CountedPurple & smoothPurple & shrunkenYellow & smoothYellow & shrunken19,20,22,20,20 = 1016,7,5,5,7 = 306,5,4,5,5 = 251,1,2,0,0 = 4TOTAL 1603. Did you obtain a 9:3:3:1 ratio? To determine if the deviations from your observed data are due to chance aloneor if the data is significantly different, you need to use a chi square test. The table below will help you make thecalculations.Expected NumberObserved Number [Observed - Expected ]²+ еxpectedPurple & smoothPurple & shrunkenTotal x 9/16 = 90101(101-90)^2/90 = 1.34Total x 3/16 = 3030(30-30)^2/30 = 0Yellow & smoothTotal x 3/16 = 3025(25-30)^2/30 = 0.83Yellow & shrunkenTotal x 1/16 = 104|(4-10)^2/10 = 3.65.77CHI SQUARE VALUE ========>(add the numbers from the rows above)4. Now determine if your chi square value is a good fit with your data. Your degrees of freedom (df) is the numberof possible phenotypes minus 1. In your case, 4 - 1 = 3. Find the number in that row that is closest to your chisquare value. Circle that number.5. Explain what it means to have a &#34;good fit&#34; or a &#34;poor fit&#34;. Does you chi square analysis of real corn data supportthe hypothesis that the parental generation was PpSs x PpSs?Chi Square Problem SetGood Fit Between Ear & DataPoor Fit1. Problem: A large ear of corn has a total of433 grains, including 271 Purple & starchy, 73Purple & sweet, 63 Yellow & starchy, and 26Yellow & sweet.df.90.70.60.5020.10.05.011.02.15.31461.642.713.856.64Your Tentative Hypothesis: This ear ofcorn was produced by a dihybrid cross(PpSs x PpSs) involving two pairs ofheterozygous genes resulting in atheoretical (expected) ratio of 9:3:3:1.2.21.711.051.393.224.605.999.21.581.421.852.374.646.257.8211.3441.062.202.783.365.997.789.4913.28Objective: Test your hypothesis using chisquare and probability values.

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